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Alik [6]
3 years ago
13

write the standard equation of a circle that is tangent to the x-axis with the center located at (2,4)​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

Step-by-step explanation:

radius=4 as it is tangent to x-axis.

y co-ordinate of center is 4 so radius=4

eq. of circle is (x-2)²+(y-4)²=4²

or x²-4x+4+y²-8y+16=16

or x²+y²-4x-8y+4=0

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3 years ago
Find the surface area of the cylinder. radius of 6. height of 7.
Sauron [17]

Answer:

SA = 156π

Step-by-step explanation:

The formula for surface area of a cylinder is

SA = 2πr² + 2πrh   where r is the base radius, and h is the height.

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SA = 2π(6²) + 2π(6)(7)

SA = 2π(36) + 2π(42)

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3 0
3 years ago
Read 2 more answers
Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

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