Question

A baseball field is in the shape of a square that is 90 feet on a side as shown. A player catches a ball at point x, which is three-quarters of the way between 2nd base & 3rd base, and throws the ball to 1st base.
What is the distance the player throws the call?

Answer 1

Answer:

The distance the player throws the ball is $112.5\ ft$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In the right triangle ABX

$AB=90\ ft$

$BX=(3/4)90=67.5\ ft$

XA --------> is the distance the player throws the ball (hypotenuse of the right triangle)

Applying the Pythagoras Theorem

$XA^{2}=AB^{2}+BX^{2}$

substitute the values

$XA^{2}=90^{2}+67.5^{2}$

$XA^{2}=12,656.25$

$XA=112.5\ ft$