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nirvana33 [79]
4 years ago
13

@Texischic101 Write 987% in decimal form. A) .0987 B) .987 C) 9.87 D) 98.7

Mathematics
2 answers:
torisob [31]4 years ago
7 0

The decimal form of 987% is 0.987.

Alex73 [517]4 years ago
7 0

the answer is  0.987 im pretty sure

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What is the property of <br><br> a(ab)+(ab)b
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Communitive Property
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Convert y=x squared +64x + 12 into graphing form
guajiro [1.7K]
To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \ of \ a \ function \ into \ vertex \ form \\ \\ y = a(x - h)^2 + k ,\\ \\ we \ have \ to \ write \ the \ equation \ in \ the \ complete \ square \ form \ and \ vertex(h, k) \ is \ given \ by:

h = \frac{-b}{2a} , \ \ k = c -\frac{b^2}{4a} \\ \\y = a(x - h)^2+k

opens   up for a > 0, and  down for a < 0

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3 0
4 years ago
Find the distance between points M and N. and if anyone could kinda explain how they got it so i can do the next ones on my own
WINSTONCH [101]

Answer:

\sqrt{13} = D

Step-by-step explanation:

Method #1

We can draw a <em>right triangle</em> on the graph upon where the points are located and use the Pythagorean Theorem:

{a}^{2} + {b}^{2} = {c}^{2}

{3}^{2} + {2}^{2} = {c}^{2}

9 + 4 = {c}^{2}

13 = {c}^{2}

\sqrt{13} = c

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

_______________________________________________

Method #2

We can use the Distance Formula:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

<em>N</em>[−3, 2] <em>M</em>[−6, 0]

\sqrt{[3 - 6]^{2} + [0 + 2]^{2}} = D

\sqrt{[-3]^{2} + 2^{2}} = D

\sqrt{9 + 4} = D

\sqrt{13} = D

* Whenever we talk about distance, we ONLY want the NON-NEGATIVE root.

** You see? It does not matter which method you choose, as long as you are doing the work correctly.

I am delighted to assist you anytime.

4 0
3 years ago
Read 2 more answers
Which series of transformations shows that pentagon A is congruent to pentagon B?
Fantom [35]
The <u>correct answer</u> is:

B) A 90° counterclockwise rotation about the origin, followed by a reflection across the x-axis, followed by a translation 8 units right and 1 unit up.

Explanation:

The coordinates of the <u>points of the pre-image</u> are:
(3, 1)
(3, 4)
(5, 7)
(6, 5)
(6, 2)

The coordinates of the <u>points of the image</u> are:
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A 90° counterclockwise rotation about the origin negates the y-coordinate and switches it and the x-coordinate.  Algebraically,
(x,y)→(-y,x).

When this is applied to our points, we get:
(3, 1)→(-1, 3)
(3, 4)→(-4, 3)
(5, 7)→(-7, 5)
(6, 5)→(-5, 6)
(6, 2)→(-2, 6)

A reflection across the x-axis negates the y-coordinate.  Algebraically,
(x, y)→(x, -y).

Applying this to our new points, we have:
(-1, 3)→(-1, -3)
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(-5, 6)→(-5, -6)
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A translation 8 units right and 1 unit up adds 8 to the x-coordinate and 1 to the y-coordinate.  Algebraically,
(x, y)→(x+8, y+1).

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(-5, -6)→(-5+8,-6+1) = (3, -5)
(-2, -6)→(-2+8,-6+1) = (6, -5)

These match the coordinates of the image, so this is the correct series of transformations.
3 0
4 years ago
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