Question

What is the value of the charge that experiences a force of 2.4 × 10–3 n in an electric field of 6.8 × 10–5 n/c?

Answer 1

Answer:

The value of charge is 35.3 C

Explanation:

Given:

Force $F = 2.4 \times 10^{-3}$ N

Electric field $E = 6.8 \times 10^{-5} \frac{N}{C}$

According coulomb's law,

  $F = qE$

Where $q =$ charge that experience a force,

For finding the value of charge,

    $q = \frac{F}{E}$

    $q = \frac{2.4 \times 10^{-3} }{6.8 \times 10^{-5} }$

     $q = 35.3$ C

Therefore, the value of charge is 35.3 C