A load of 25 kg is applied to the lower end and of a steal wire of length 25 m and thickness 3.0mm .The other end of wire is sus
1 answer:
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Answer:
I = 6 A
Explanation:
Given that,
Power of an electric heatr, P = 1.38 kW
The voltage of the mains supply, V = 230 V
We need to find the current through the heater. The electric power in terms of voltage and current is given by :
So, the current through an electric heater is 6 A.
Answer:
A. Attractive
B. ( μ₀I² ) / ( 2πd )
Explanation:
A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.
B. Suppose that two wires of length and
both carry the current
in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -
= μ₀I / 2πd
The force experienced by wire 2 should thus be -
= I(
)
= I
Sin( 90 )
= I
( μ₀I / 2πd )
Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...
( /
) = ( μ₀I² ) / ( 2πd ) ... which is our solution