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3 years ago

Due to a leak, the amount of water in a pool is decreasing by 5858 gal every hour.

1 answer:

4 0

Here is the solution to the given problem above.
Given the the amount of water in a pool is decreasing 5/8 gallon every hour.
And what would be the change in the number of gallons after 3/4 hour. So what we are going to do is just to multiply 5/8 by 3/4. And the result would be 15/32. The total change in the number of gallons of water in the pool after 3/4 hour would be 15/32 gallons.

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What is an equation in point-slope form for the line perpendicular to y = 7x + 14 that contains (3, –7)?

umka21 [38]

The equation of the perpendicular line is y + 7 = -1/7(x - 3)

<h3>How to determine the line equation?</h3>

The equation is given as

y = 7x + 14

Also, from the question

The point is given as

Point = (3, -7)

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 7

This means that the slope of y = 7x + 14 is 7

So, we have

m = 7

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -1/7

The equation of the perpendicular lines is then calculated as

y = m(x - x₁) +y₁

Where

m = -1/7

(x₁, y₁) = (3, -7)

So, we have

y = -1/7(x - 3) - 7

Evaluate

y = -1/7(x - 3) - 7

Add 7 to both sides

y + 7 = -1/7(x - 3)

Hence, the perpendicular line has an equation of y + 7 = -1/7(x - 3)

Read more about linear equations at

brainly.com/question/4074386

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8 0

1 year ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

I need helppppp asap

11111nata11111 [884]

Answer: A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The sum of 5 consecutive integers is 100. What is the first number in this sequence?

yanalaym [24]

So we can call first number "n"

Then all five integers would be n, n+1, n+2, n+3, n+4

So sum of them would be 5n + 10 = 100

Now you can solve for n:

5n + 10 = 100

5n = 90

n = 18

Verify: 18 + 19 + 20 + 21 + 22 = 100. All good.

So answer is 18

5 0

3 years ago

Rachael has a rope 5 m 32 cm long that she cut into two pieces. One piece is 249 cm long. How many centimeters long is the other

satela [25.4K]

1 m = 100 cm, so 5 m = 500 cm plus the 32 cm, so she has a rope that is 532 cm long.

532 - 249 = 283 cm

So the other piece of rope is 283 cm long.

4 0

3 years ago