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LUCKY_DIMON [66]
3 years ago
12

Two vertices of a right triangle have coordinates (5,12)and(11,12).the segment that connects these ponits is a leg of tje triang

le.which coordinate pair for the third vertex would create a right triangle?
A.(11,4)
B.(8,12)
C.(19,12)
D.(8,20)
Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0
Both point (5,12) and (11,12) lie on the horizontal line  y=12.

If these two points is a leg of the triangle, the other leg must be perpendicular to the horizontal line, that is, the other leg must be vertical, but passing through either (5,12) or (11,12), i.e. lies on either the vertical line x=5 or x=11.
There is only one point that passes through x=11, i.e. point A(11,4).


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3 years ago
( 2/3 a^2b^2)^2·(−3ab)^4
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Solving the expression: (\frac{2}{3}a^2b^2)^2(-3ab)^4 we get 36a^8b^8

Step-by-step explanation:

We need to solve the expression: (\frac{2}{3}a^2b^2)^2(-3ab)^4

Solving:

Using exponent rule:(a^b)^c=a^{bc} and another rule: x^a.x^b=x^{a+b}

(\frac{2}{3}a^2b^2)^2(-3ab)^4\\=\frac{4}{9}a^4b^4(81a^4b^4)\\=\frac{4}{9}*81a^{4+4}b^{4+4}\\=4*9a^8b^8\\=36a^8b^8

So, solving the expression: (\frac{2}{3}a^2b^2)^2(-3ab)^4 we get 36a^8b^8

Keywords: Solving Exponents

Learn more about Solving Exponents at:

  • brainly.com/question/13174254
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2 years ago
Read 2 more answers
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