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2 years ago

Choose the equation that is equivalent to: 4(8x+6)=20

Mathematics

2 answers:

KengaRu [80]2 years ago

7 0

Answer:

Step-by-step explanation:

32x + 24 = 20

24 - 24= 0

20 - 24= -4

32x = -4

32x/32

-4/32= -8

X= -1/8

Alenkinab [10]2 years ago

4 0

Answer:

Step-by-step explanation:

A. the 4 cannot go past the equal sign. The 4 only changes what is inside the brackets. Not the answer.

B: You could use B if it was done correctly.

8x + 6 = 5 The 4 can only affect the right hand side.

C. is Correct.

D. I really don't see the steps to get this. In any event it is not correct.

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3 years ago

Solution for -4 5/6 +5 1/3

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Answer:

1/2

Step-by-step explanation:

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3 years ago

Please help, the question below

Licemer1 [7]

Answer:

$\sf R=\left(3, -\dfrac{5}{4}\right)$

Step-by-step explanation:

Given:

P = (1, 5)
Q = (-2, 3)
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R lies on line x = 3
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If point R lies on the line x = 3, then the x-value of point R is 3.

⇒ a = 3

Distance between two points

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

(where (x₁, y₁) and (x₂, y₂) are the two points)

Use the distance formula to derive equations for PR and QR.

Let (x₁, y₁) = P = (1, 5)

Let (x₂, y₂) = R = (3, b)

$\begin{aligned} \sf PR & =\sf \sqrt{(3-1)^2+(b-5)^2}\\ & = \sf \sqrt{4+(b-5)^2} \end{aligned}$

Let (x₁, y₁) = Q = (-2, 3)

Let (x₂, y₂) = R = (3, b)

$\begin{aligned} \sf QR & =\sf \sqrt{(3-(-2))^2+(b-3)^2}\\ & = \sf \sqrt{25+(b-3)^2} \end{aligned}$

As PR = QR, equate the derived equations and solve for b:

$\begin{aligned} \sf PR & = \sf QR \\\sf \sqrt{4+(b-5)^2} & = \sf \sqrt{25+(b-3)^2}\\\sf 4+(b-5)^2 & = \sf 25+(b-3)^2\\\sf 4+b^2-10b+25 & = \sf 25 + b^2-6b+9\\\sf b^2-10b+29 & = \sf b^2 -6b +34\\\sf -10b+29 & = \sf -6b + 34\\\sf -4b & = \sf 5\\\sf b & = -\dfrac{5}{4}\end{aligned}$

Substitute the found values of a and b to find the coordinates of R:

$\sf R=(a,b)=\left(3, -\dfrac{5}{4}\right)$

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