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Sauron [17]
3 years ago
12

What is the maximum angular momentum Lmax that an electron with principal quantum number n = 2 can have? Express your answer in

units of ℏ.
Physics
1 answer:
butalik [34]3 years ago
4 0

Answer:

L_{max} = 1.414 ℏ

Given:

Principle quantum number, n = 2

Solution:

To calculate the maximum angular momentum, L_{max}, we have:

L_{max} = \sqrt {l(1 + l)}                              (1)

where,

l = azimuthal quantum number or angular momentum quantum number

Also,

n = 1 + l

2 = 1 + l

l = 1

Now,

Using the value of l = 1 in eqn (1), we get:

L_{max} = \sqrt {1(1 + 1)} = \sqrt 2

L_{max} = 1.414 ℏ

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