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3 years ago

Lunar phases occur when the moon appears to change shape as seen from earth. What causes different phases of the moon?.

1 answer:

meriva3 years ago

8 0

Answer: The moon is said to be in full phase when the illuminated half of the moon is fully in position for us to see it. The "new moon" phase of the lunar cycle happens when the sun, moon, and earth are located in a straight line, with the moon between the earth and the sun. The moon is said to be in a "waxing" phase when it is moving from the new moon phase into the full moon phase. During this time, the amount of visible, illuminated moon will be gradually growing. The moon is said to be in a "waning" phase when it is moving from the full moon phase into the new moon phase. During this time, the visible portion of the moon will appear to be shrinking. A crescent moon occurs close to the new and full moon stages, whether the moon is waxing or waning. At this time, only a small sliver of the illuminated moon is visible to us.

Explanation:

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The 1st Law of Thermodynamics is a statement about (A) Temperatures scales (B) Whether a process can proceed in a specific manne

weqwewe [10]

Answer:

Energy conservation.

Explanation:

The 1st Law of Thermodynamics is a statement about energy conservation. It states that $\Delta U=Q-W$ , which means that if we substract the work W done by the system to the heat Q given to the system we get the change in the internal energy $\Delta U$ , so any excess in energy given to the system appears as internal energy, stating that energy is conserved.

3 0

4 years ago

Electrical power is transmitted from power plants to consumers–sometimes over very long distances– through conducting power line

sergeinik [125]

There is more wire to travel through,farther distance, and a higher possibility of other disruptions. Please Mark Brainliest!!!

7 0

3 years ago

which of the glass lenses above, when placed in air, will cause rays of light (parallel to the central axis) to converge?

777dan777 [17]

Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

Learn more about the convex lens here:

brainly.com/question/12847657

#SPJ4

3 0

1 year ago

A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is

harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

Where,

$d_g =$ Depth of glass

$n_w =$ Refraction index of water

$n_g =$ Refraction index of glass

$n_{air} =$ Refraction index of air

$d_w =$ Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

$d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})$

$d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})$

$d'w = 4.041cm$

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0

3 years ago

Help with speed problems #1-3

-Dominant- [34]

1. Each plot represents the meters traveled by both the Hare and the Tortoise over a certain period of time (minutes).

2. The Tortoise lines show it lines is steadily increasing over a period of time. So as more time elapses the faster the tortoise becomes it travels more meters. The Tortoise line shows steady acceleration.

3. The Hare in the first 5 minutes had a rapid fast advancement up to 40 meters. But for the 5-20 mins. period the Hare did not move at all. Its speed stayed at the same place. But towards the end 20-25 mins. marks the Hare started moving again. At the end the Hare at first had a rapid acceleration but stopped for a long time then it sped up briefly.

8 0

3 years ago