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Fiesta28 [93]
2 years ago
15

The form of energy stored in food

Physics
2 answers:
Effectus [21]2 years ago
7 0
Chemical energy *.*
m_a_m_a [10]2 years ago
4 0

Answer:

chemical energy

Explanation:

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A string of 26 identical Christmas tree lights are connected in series to a 120 V source. The string dissipates 73 W. What is th
spin [16.1K]

To solve this problem we will apply the concepts related to Ohm's law and Electric Power. By Ohm's law we know that resistance is equivalent to,

R_{eq}= \frac{V}{I}

Here,

V = Voltage

I = Current

While the power is equivalent to the product between the current and the voltage, thus solving for the current we have,

P=VI \rightarrow I = \frac{P}{V}

I =0.608 A

Applying Ohm's law

R_{eq} = \frac{120V}{0.608A}

R_{eq} = 197.4\Omega

Therefore the equivalent resistance of the light string is 197.4\Omega

6 0
2 years ago
What do the law of superposition and the law of inclusion have in common? (1 point) 1. Both laws are about matching fossils in d
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Answer:

its b

i took the test

Explanation:

4 0
3 years ago
Given the height of rod,length of shadow of tree and length of shadow of the rod, estimate the height of the tree? Given:height
diamong [38]

Answer:

1000 cm.

Explanation:

To obtain the estimated tree height :

(Height of rod / length of rod shadow) = (height of tree / length of tree shadow)

Substituting values into the formula :

(150cm / 120 cm) = (height of tree / 800 cm)

Using cross multiplication :

Height of tree * 120 = 150 * 800

Height of tree = (150 * 800) / 120

Height of tree = 120,000 / 120

Height of tree = 1000

Hence, estimate height of tree = 1000 cm

5 0
2 years ago
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
olya-2409 [2.1K]

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

5 0
3 years ago
In our first example we will consider a very simple application of Newton’s second law. A worker with spikes on his shoes pulls
sweet-ann [11.9K]

Answer:

Acceleration=0.5m/s^2

Speed=0.67 m/s

Explanation:

We are given that

Horizontal force=F=20 N

Mass of box=m=40 kg

We know that

Acceleration=a=\frac{F}{m}

Using the formula

Acceleration of box=\frac{20}{40}=0.5m/s^2

The acceleration of the box=0.5m/s^2

Initial velocity=u=0

Force=F=30 N

Distance=s=0.3 m

a=\frac{30}{40}=\frac{3}{4} ms^{-2}

v^2-u^2=2as

Substitute the values

v^2-0=2\times \frac{3}{4}\times 0.3=0.45

v^2=0.45

v=\sqrt{0.45}=0.67m/s

Hence, the speed of the box after it has  been pulled a distance of 0.3 m=0.67 m/s

4 0
2 years ago
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