Answer:
11.) g = 3.695 m/s^2
12.) g = 8.879 m/s^2
13.) E = 8127 N/C
Explanation:
11.) Given that the
Mercury mass M = 3.3 × 10^23kg
Radius r = 2.44 ×10^6 m
Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2
Gravitational field strength g can be calculated by using the formula below
g = GM/r^2
Substitutes all the parameters into the formula
g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2
g = 2.2×10^13/5.954×10^12
g = 3.695 m/s^2
12.) Given that the
Venus mass M = 4.87×10^24kg
Radius r = 6.05 × 10^6 m
Using the same formula for gravitational field strength g
g = GM/R2
Substitute all the parameters into the formula
g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2
g = 3.25×10^14/3.66×10^13
g = 8.879 m/s^2
13.) Given that the
Charge = 2.26 nC = 2.26×10^-9
Distance d = 0.05m
Electric field strength E can be calculated by using the formula below
E = Kq/d^2
Where
K = electrostatic constant 8.99 × 10^9 Nm2/C2
Substitutes all the parameters into the formula
E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2
E = 20.3174/2.5×10^-3
E = 8126.96 N/C
Answer:
48 m/s
Explanation:
The time is 10 seconds
The speed of the car after 10 seconds when the relationship is 4.8 m/s^2 × time can be calculated as follows
= 4.8 × 10
= 48
Hence the speed is 48 m/s
Answer:
The magnitude of angular acceleration is 
.
Explanation:
Given that,
Initial angular velocity, 
When it switched off, it comes o rest, 
Number of revolution, 
We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :
So, the magnitude of angular acceleration is . Hence, this is the required solution.
<h2>The velocity of car was m m/s </h2>
Explanation:
When the car skids , its centripetal force is provided by frictional force .
Here centripetal force F = 
here v is the velocity of car and r is the radius of the curve .
The frictional force f = μ R
here μ is the coefficient of kinetic friction and R is normal reaction
Thus f = m g
On horizontal road R = mg
Thus F = f at the time of skid .
Thus v = 
= 
= 9 m/s
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