Charges q1 and q2 exerts repulsive forces of 10N on each other what is the repulsive force when their separation is decreasing s o that their final separation is 80% of their initial separation ?
1 answer:
Answer:
15.6 N
Explanation:
Coulomb's law:
F = k q₁ q₂ / r²
At distance r:
10 N = k q₁ q₂ / r²
At distance 0.8r:
F = k q₁ q₂ / (0.8r)²
F = k q₁ q₂ / (0.64r²)
F = 10 N / 0.64
F ≈ 15.6 N
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