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pochemuha
3 years ago
15

Wegener developed he hypothesis that Earth's landmasses had once been fused together, and hen slowly broke apart in a process ca

lled. a:continental drift b:subduction c:Pangea d:divergence
Physics
1 answer:
ivanzaharov [21]3 years ago
4 0

Solution: C. Pangea

The hypothesis of Continental drift suggests that in past, there was only one landmass on the Earth -Pangaea which drifted apart due to movement of plate tectonics causing earthquake. This hypothesis is supported by many evidences which includes presence of similar fossils on different landmasses, common land features such as widespread presence of glacial sediments etc.

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An airplane travels 2100 km at a speed of 1000 km/h. It then encounters a headwind which slows it to 800 km/h for the next 1300
Sidana [21]
I don’t get it I need help
5 0
3 years ago
Suppose the farthest distance a person can see without visual aid is 53 cm.
natita [175]

Answer: a. 53cm b. Diverging c. 0.02dioptres

Explanation:

Since the person in question cannot see far object clearly, it shows that the individual is suffering from myopia (short sightedness).

If the object distance (u) is 53cm. for the person to be able to see far way, it means the image must be at infinity. This shows image distance v is infinity. Using the lens formula

1/f = 1/u+1/v

1/f = 1/53 + 1/Infinity

1/f = 1/53 + 0

f=53cm

b) The lens used is concave lens (diverging lens) to diverge all rays outwards

c) Power of a lens P will be 1/53.

P = 0.02dioptres

8 0
3 years ago
How many revolutions per minute would a 23 m -diameter Ferris wheel need to make for the passengers to feel "weightless" at the
kirza4 [7]

Answer:

Approximately 6.2\; {\rm rpm}, assuming that the gravitational field strength is g = 9.81\; {\rm m\cdot s^{-2}}.

Explanation:

Let \omega denote the required angular velocity of this Ferris wheel. Let m denote the mass of a particular passenger on this Ferris wheel.

At the topmost point of the Ferris wheel, there would be at most two forces acting on this passenger:

  • Weight of the passenger (downwards), m\, g, and possibly
  • Normal force F_\text{normal} that the Ferris wheel exerts on this passenger (upwards.)

This passenger would feel "weightless" if the normal force on them is 0- that is, F_\text{normal} = 0.

The net force on this passenger is (m\, g - F_\text{normal}). Hence, when F_\text{normal} = 0, the net force on this passenger would be equal to m\, g.

Passengers on this Ferris wheel are in a centripetal motion of angular velocity \omega around a circle of radius r. Thus, the centripetal acceleration of these passengers would be a = \omega^{2}\, r. The net force on a passenger of mass m would be m\, a = m\, \omega^{2}\, r.

Notice that m\, \omega^{2} \, r = (\text{Net Force}) = m\, g. Solve this equation for \omega, the angular speed of this Ferris wheel. Since g = 9.81\; {\rm m\cdot s^{-2}} and r = 23\; {\rm m}:

\begin{aligned} \omega^{2} = \frac{g}{r}\end{aligned}.

\begin{aligned} \omega &= \sqrt{\frac{g}{r}} \\ &= \sqrt{\frac{9.81\; {\rm m \cdot s^{-2}}}{23\; {\rm m}}} \\ &\approx 0.653\; {\rm rad \cdot s^{-1}} \end{aligned}.

The question is asking for the angular velocity of this Ferris wheel in the unit {\rm rpm}, where 1\; {\rm rpm} = (2\, \pi\; {\rm rad}) / (60\; {\rm s}). Apply unit conversion:

\begin{aligned} \omega &\approx 0.653\; {\rm rad \cdot s^{-1}} \\ &= 0.653\; {\rm rad \cdot s^{-1}} \times \frac{1\; {\rm rpm}}{(2\, \pi\; {\rm rad}) / (60\; {\rm s})} \\ &= 0.653\; {\rm rad \cdot s^{-1} \times \frac{60\; {\rm s}}{2\, \pi\; {\rm rad}} \times 1\; {\rm rpm} \\ &\approx 6.2\; {\rm rpm} \end{aligned}.

3 0
2 years ago
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include
Kaylis [27]

The electric filed in V/m is 1.58 * 10^6 V/m

<h3>What is the electric field?</h3>

We know that the electric field is obtained as the ratio of the voltage to the distance that separates the plates.

Thus;

E = V/d

E = electric field

V = voltage

d = distance of separation

E = 24 * 10^3 V/1.52 * 10^-2 m

E = 1.58 * 10^6 V/m

Learn more about electric field :brainly.com/question/8971780

#SPJ1

7 0
2 years ago
The angular momentum about the center of the planet and the total mechanical energy will be conserved regardless of whether the
ValentinkaMS [17]

Answer:

True

Explanation:

The angular momentum around the center of the planet and the total mechanical energy will be preserved irrespective of whether the object moves from large R  to small R. But on the other hand the kinetic energy of the planet will not be conserved because it can change from kinetic energy to potential energy.

Therefore the given statement is True.

5 0
4 years ago
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