If you were told an atom was an ion, you would know the atom must have a

Physics

2 answers:

Effectus [21]3 years ago

7 0

The atom must have gained 1 or more electrons or must have lost 1 or more electrons.

sweet-ann [11.9K]3 years ago

3 0

Explanation:

In an atom number of electrons and protons are equal. it is an electrically neutral specie.

In an ion, the number of electrons and protons are not equal. There are two types of an ion :

Cation: When the number of protons are greater than number of electrons. These ions have a positive charge.
Anion : When the number of electrons are greater than number of protons. These ions have a negative charge.

Hence, if an atom is considered as an ion, then it will have an unequal number of protons and electrons.

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if a sample that is 4860 years old has 50 radium atoms remaining, how many atoms were in the original sample?

snow_lady [41]

243000, take the 4,860 and times it by 50

4 0

3 years ago

A flutist assembles her flute in a room where the speed of sound is 342m/s . When she plays the note A, it is in perfect tune wi

USPshnik [31]

Answer:

a.3Hz

b.0.0034m

Explanation:

First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.

The formula relating the length and he frequency is giving as

$f=\frac{nv}{2l}\\$ .

a.we first determine the length of the flute at the fundamental frequency i.e when <em>n</em>=1 and when the speed is in the 342m/s

Hence from

$f=\frac{nv}{2l}\\\\l=\frac{342}{2*440}\\ l=0.389m\\$ .

since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.

$f=\frac{nv}{2l} \\f=\frac{345}{2*0.389}\\f=443.4Hz$

Hence the require beat is

$B=/f_{1}-f_{2}/\\B=/440-443/\\B=3Hz$ .

b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s

using the formula

$L_{new}=\frac{v}{2f}\\\\L_{new}=\frac{345}{2*440}\\\\L_{new}=0.39204$