Answer:
The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24
.
Explanation:
Velocity is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.
In this case, the displacement is 192 m and the time period is 8 s. Replacing:

Solving:
velocity= 24 
<em><u>The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 </u></em>
<em><u>.</u></em>
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<h3>
Answer:</h3>
1.3 Amps
<h3>
Explanation:</h3>
<u>We are given;</u>
A circuit with resistors, R1 and R2
R1 = 7 Ω
R2 = 11 Ω
Voltage = 24 V
We are required to calculate the current in the circuit.
<h3>Step 1: We need to find the effective resistance.</h3>
When resistors are arranged in series, the effective resistance is calculated by;
Rt = R₁ + R₂ + R₃ + ..........Rₙ
Therefore;
Total resistance = 7 + 11
= 18 Ω
<h3>Step 2: Calculate the current in the circuit</h3>
From the ohm's law;
V = IR
Rearranging the formula;
I = V/R
Thus;
I = 24 V ÷ 18 Ω
= 1.333 Amps
= 1.3 Amps
Thus, the current in the circuit is 1.3 Amps
Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π ×
................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second
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