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2 years ago

Why do planets speed up as they get closer to the sun?:

Physics

1 answer:

Serggg [28]2 years ago

5 0

Answer:

Explanation:

Gravity is the main reason that make our planets to pull each other

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A box of mass 1 kg is hung from a spring scale. The reading on the spring scale is approximately 10N. What would be the reading

8090 [49]

The answer will be 50N.
This is because the spring reads weight and weight is mass times acceleration due to gravity.5kg*10m/s2=50N

8 0

2 years ago

Read 2 more answers

If my glass is filled with ice and water, will it overflow once the ice has melted?

meriva

No because it will contain the same amount of mass, just in different forms.

7 0

3 years ago

Read 2 more answers

A typical cell phone charger is rated to transfer a maximum of 1.0 Coulomb of charge per second. Calculate the maximum number of

Alexandra [31]

Answer:

The maximum no. of electrons- $2.25\times 10^{22}$

Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

$I = \frac{Q}{t}$

Q = ne

where

n = no. of electrons

Q = charge in coulomb

I = current

Thus

Q = It

Thus the charge flow in 1. 0 h:

$Q = 1.0\times 3600 = 3600\ C$

Maximum number of electrons, n is given by:

$n = \frac{Q}{e}$

where

e = charge on an electron = $1.6\times 10^{- 19}\ C$

Thus

$n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}$

3 0

3 years ago

A supersonic jet is at an altitude of 14 kilometers flying at 1,500 kilometers per hour toward the east. At this velocity, how f

Kaylis [27]

Answer:

The jet will fly 2400 km.

Explanation:

Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.

We need to find the distance covered in 1.6 hours.

In our problem we are given speed and time, we can easily determine the distance using the following formula.

$Distance=Speed\times Time$

$Distance=1500\times 1.6=2400\ km$

So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.

3 0

3 years ago

A step index fiber has a numerical aperture of NA = 0.1. The refractive index of its cladding is 1.465. What is the largest core

Vladimir [108]

Answer:

diameter = 9.951 × $10^{-6}$ m

Explanation:

given data

NA = 0.1

refractive index = 1.465

wavelength = 1.3 μm

to find out

What is the largest core diameter for which the fiber remains single-mode

solution

we know that for single mode v number is

V ≤ 2.405

and v = $\frac{2*\pi *r}{ wavelength} NA$

here r is radius

so we can say

$\frac{2*\pi *r}{ wavelength} NA$ = 2.405

put here value

$\frac{2*\pi *r}{1.3*10^{-6}} 0.1$ = 2.405

solve it we get r

r = 4.975979 × $x^{-6}$ m

so diameter is = 2 × 4.975979 × $10^{-6}$ m

diameter = 9.951 × $10^{-6}$ m

3 0

3 years ago