Answer:
o The result of a chemical change is a different composition; in a physical change, the composition remains the same.
Explanation:
In a chemical change, new kinds of matter are produced although the atoms are the same.
For physical changes, no new kinds of matter formed. Only the state of substances changes.
- Most chemical changes are usually irreversible
- Physical changes are reversible in most parts.
- Changes in state and form are salient characteristics of physical changes.
- When new products are formed from the reactants, it is an indicator of a chemical change.
Answer: The first answer for the first problem, and the 2nd answer for the second problem
Explanation: For the first one, if it is absolute zero, the molecules would not move at all.
For the second one, the temperature of the sample will increase due to the movement.
Answer:
Explanation:
Work
Other units Foot-pound, Erg
In SI base units 1 kg⋅m2⋅s−2
Derivations from other quantities W = F ⋅ s W = τ θ
Dimension M L2 T−2
Idk if this is what u are looking for but i hope this help.:)
A Post-and-lintel is a system that uses vertical posts which are separated to
support a horizontal beam.
A Post-and-lintel system is commonly used in architecture and involves the
system where horizontal structures are held by vertical ones with the
presence of spaces between them.
In this scenario, we were told the system uses vertical posts which are
separated to support a horizontal beam which makes Post-and-lintel the
most appropriate choice.
Read more on brainly.com/question/8777125
Answer:
1.98 atm
Explanation:
Given that:
Temperature = 28.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
n = 1
V = 0.500 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
P × 0.500 L = 1 ×0.0821 L atm/ K mol × 301.15 K
⇒P (ideal) = 49.45 atm
Using Van der Waal's equation
R = 0.0821 L atm/ K mol
Where, a and b are constants.
For Ar, given that:
So, a = 1.345 atm L² / mol²
b = 0.03219 L / mol
So,
⇒P (real) = 47.47 atm
Difference in pressure = 49.45 atm - 47.47 atm = 1.98 atm
