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3 years ago

Which of the following determines the natural frequency of an object?

Physics

1 answer:

Vinvika [58]3 years ago

3 0

Answer:

Explanation:

The longer an object, the slower it vibrates and since frequency is the number of oscillations an object makes per second, then you can say the longer the object, the lower the frequency, and the inverse is true.

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Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recen

ddd [48]

Answer:

Fringe width = 21 mm

Explanation:

Fringe width is given by the formula

$\beta = \frac{\Lambda L}{d}$

here we know that

$\Lambda = 564 nm$

L = 4.0 m

d = 0.108 mm

now from above formula we will have

$\beta = \frac{(564 \times 10^{-9})(4.0 m)}{0.108\times 10^{-3}}$

$\beta = 0.021 meter$

so fringe width on the wall will be 21 mm

7 0

3 years ago

In an inertia balance, a body supported against gravity executes simple harmonic oscillations in a horizontal plane under the ac

avanturin [10]

Answer:

2) f = 0.707 Hz

Explanation:

Given m₁ = 1.0 kg , f₁ = 1.0 Hz

So using the equation

f₁ = ( 1 / 2 π ) * √K / m₁

Solve to determine K' constant of spring

K = m * ( 4 π ² * f ² )

K = 1.0 kg * ( 4 π ² 1.0² Hz )

K = 39.4784176

So given 2.0 kg the frequency can be find using formula

f₂ = ( 1 / 2 π ) * √K / m₂

f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg

f₂ = 0.707 Hz

4 0

3 years ago

Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1.4 kW/m2. (a) Assuming that Earth (and

baherus [9]

To solve the problem we will require the concept of Force as a definition of pressure and Area, and the concept of light pressure itself determined by the relationship between intensity and the speed at which light travels. We will match the terms and find the desired force value,

$F = PA$

Here,

P = Pressure

A = Area

Pressure due to the light of the sun will be

$P= \frac{I}{c}$

Here,

I = Intensity

c = Speed velocity

Equation both therms we have that

$F = \frac{IA}{c}$

We have a circular area then

$F = \frac{I(\pi r^2)}{c}$

Replacing with our values (Adding the radius of the Earth)

$F = \frac{(1.4*10^3W/m^2)(\pi (6.32*10^6m)^2)}{3.0*10^8m/s}$

$F = 6.0*10^8N$

Therefore the Force on Earth due to radiation pressure is $6*10^8N$

4 0

3 years ago

The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo

boyakko [2]

Answer:

r = 255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = 22 m/s²

v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

4 0

3 years ago

Guys please help me out I’ll give extra points

zvonat [6]

Answer: h = 3.34 m

Explanation:

If the hat is thrown straight up, then at its highest point it has no motion and no kinetic energy. All energy is potential energy

PE = mgh

h = PE/mg = 4.92 / (0.150(9.81)) = 3.34352... ≈3.34 m

8 0

3 years ago