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kumpel [21]
4 years ago
10

While following the directions on a treasure map, a pirate walks 37.0m north and then turns and walks 8.5m east. What is the mag

nitude of his resultant displacement?
A.) 38m
B.) 45.5m
C.) 28.5m
Physics
2 answers:
muminat4 years ago
8 0

Answer:

Resultant displacement, R = 38 meters

Explanation:

Distance covered the pirate, d = 37 m (due north)

Distance covered by pirate, d' = 8.5 m (due east)

Let R is the magnitude of his resultant displacement. The displacement of an object is equal to the shortest path covered by it. It can be calculated as :

R=\sqrt{d^2+d'^2}

R=\sqrt{(37)^2+(8.5)^2}

R = 37.96 meters

So

R = 38 meters

So, the magnitude of his resultant displacement is 38 meters. Hence, this is required solution.

vekshin14 years ago
4 0

Answer:

A.

Explanation:

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andrew-mc [135]

Answer:

4.03\times10^{7}N[/tex], 135°

Explanation:

charge, q = 7 mC = 0.007 C

charge, - q = - 7 mC = - 0.007 C

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Let the force on charge placed at C due to charge placed at D is FD.

F_{D}=\frac{kq^{2}}{DC^{2}}

F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N

The direction of FD is along C to D.

Let the force on charge placed at C due to charge placed at B is FB.

F_{B}=\frac{kq^{2}}{BC^{2}}

F_{B}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N

The direction of FB is along C to B.

Let the force on charge placed at C due to charge placed at A is FA.

F_{A}=\frac{kq^{2}}{AC^{2}}

F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1 \times\sqrt{2} \times 0.1 \times\sqrt{2}}=2.205 \times 10^{7}N

The direction of FA is along A to C.

The net force along +X axis

F_{x}=F_{A}Cos45-F_{D}

F_{x}=2.205\times10^{7}Cos45-4.41\times10^{7}=-2.85\times10^{7}N

The net force along +Y axis

F_{y}=F_{B}-F_{A}Sin45

F_{y}=4.41\times10^{7}-2.205\times10^{7}Sin45=2.85\times10^{7}N

The resultant force is given by

F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{(-2.85\times10^{7})^{2}+(2.85\times10^{7})^{2}}

F = 4.03\times10^{7}N

The angle from x axis is Ф

tan Ф = - 1

Ф = -45°

Angle from + X axis is 180° - 45° = 135°

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3 years ago
What is the average speed of a train that travels at 100km/hr for 6 hours and then 120km/hr for 5 hours
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Answer:

Explanation:

Average speed = Total distance / Total time.

100 km/hr

r = 100 km / hr

t = 6 hours

d = 6 * 100 = 600 km

120 km / hr

r = 120 km / hr

t = 5 hour

d = 120 * 5

d = 600 km

Total distance = 600 + 600 = 1200 km

Total time = 5 hour + 6 hours = 11 hours.

Average speed = 1200 km / 11 hours = 109.1

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( WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST AND SHOWS WORK) A car weighs 15300 N. What is its mass?
mylen [45]

Answer:

Mass, m = 1561.23kg

Explanation:

Given the following data;

Weight = 15300N

We know that acceleration due to gravity is equal to 9.8m/s²

To find mass;

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, the weight of an object is given by the formula;

Weight, W = mg

Where;

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  • g is the acceleration due to gravity measured in meters per seconds square.

Substituting into the equation, we have;

15300 = m*9.8

m = \frac {15300}{9.8}

<em>Mass, m = 1561.23 Kg</em>

<em>Therefore, the mass of the car is 1561.23 kilograms.</em>

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