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Kipish [7]
3 years ago
13

A 1502.7 kg car is traveling at 33.1 m/s when

Physics
1 answer:
Bond [772]3 years ago
5 0

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

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Read 2 more answers
A transverse, travelling wave on a chord is represented by = 0.22sin (5.6 + 34) where and are in meters and is in seconds. For t
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Answer:

A)  1.122 m

B)  5.4 hertz

C)  6.06 m/s ( towards negative  x axis )

D)  0.22

E)  max speed = amplitude * 34

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Explanation:

The travelling wave = D = 0.22sin ( 5.6x + 34t)

this wave is represented in the form : D = Asin ( kx + wt)

A) wavelength

k = 2\pi / v

v = wavelength

k = 5.6

therefore wavelength ( v ) from the equation = 2\pi / 5.6 = 1.122 m

B ) frequency

w = 2\pif

w = 34

f = frequency

therefore f = w / 2\pi  = 34 / 2\pi = 5.4 hertz

C ) velocity

speed = f v

v = 5.4 * 1.122 = 6.06 m/s ( towards negative  x axis )

D) amplitude

A = 0.22

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max speed = amplitude * 34

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3 years ago
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