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IRINA_888 [86]
3 years ago
10

To calculate work done on an object, _____.

Physics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

D) multiply the force in the direction of motion by the distance the object moved

Explanation:

To calculate work done on an object, multiply the force in the direction of motion by the distance the object moved.

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g The potential energy of a pair of hydrogen atoms separated by a large distance x is given by U(x)=−C6/x6, where C6 is a positi
Arisa [49]

Answer:

F_x = -\frac{6 C_6}{2^7}

Attractive

Explanation:

Data provided in the question

The potential energy of a pair of hydrogen atoms given by \frac{C_6}{X_6}

Based on the given information, the force that one atom exerts on the other is

Potential energy μ = \frac{C_6}{X_6}

Force exerted by one atom upon another

F_x = \frac{\partial U}{\partial X} = \frac{\partial}{\partial X}  (-\frac{C_6}{X^6})

or

F_x = \frac{\partial}{\partial X}  (\frac{C_6}{X^6})

or

F_x = -\frac{6 C_6}{2^7}

As we can see that the C_6 comes in positive and constant which represents that the force is negative that means the force is attractive in nature

5 0
4 years ago
An attack helicopter is equipped with a 20- mm cannon that fires 88.7 g shells in the forward direction with a muzzle speed of 9
Svetradugi [14.3K]
The impulse imparted to the shells equals the change in the momentum:
Fav*(Delta t)= Delta m*v.
The mass change is
Delta m= n*m= (89.9shells)*(88.7g)=7.97Kg
So the average force is
F=((v)*(Delta m))/t= ((929)*(7.97))/4.84=1529.78 N
Since the velocity of the shells is much greater than the velocity of the helicopter, there is no need to use relative velocity.



4 0
3 years ago
Which of the following quantities are unknown?
Sauron [17]

Answer:

Charge of the alpha particle

Explanation:

6 0
3 years ago
Is it okay to keep an albino gecko
arlik [135]

Answer:

Yes

Explanation:

5 0
3 years ago
Assuming a roughly spherical shape and a density of 4000 kg/m3, estimate the diameter of an asteroid having the average mass of
vredina [299]

Explanation:

It is given that,

Density of asteroid, \rho=4000\ kg/m^3

Mass of asteroid, m=10^{17}\ kg

We need to find the diameter of the asteroid. The formula of density is given by:

\rho=\dfrac{m}{V}

V is the volume of spherical shaped asteroid, V=\dfrac{4}{3}\pi r^3

r^3=\dfrac{3M}{4\pi \rho}

r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}

r^3=\sqrt{5.96\times 10^{12}}

r = 2441311.12 m

Diameter = 2 × radius

d = 4882622.24 m

or

d=4.88\times 10^6\ m

Hence, this is the required solution.

8 0
3 years ago
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