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sp2606 [1]
3 years ago
13

Which function will have a y-intercept at –1 and an amplitude of 2?

Mathematics
2 answers:
Artyom0805 [142]3 years ago
5 0

Answer:

B

Step-by-step explanation:

edge2020 quiz

Angelina_Jolie [31]3 years ago
4 0

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

h(x)=A\sin (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

The general form of cosine function

h(x)=A\cos (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

In function, f(x)=-\sin x-1

Amplitude : |A|=1

y-intercept : -1

In function, f(x)=-2\sin x-1

Amplitude : |A|=2

y-intercept : -1

In function, f(x)=-\cos x

Amplitude : |A|=1

y-intercept : 0

In function, f(x)=-2\cos x-1

Amplitude : |A|=2

y-intercept : -1

Therefore, the correct options are B and D.

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If x is 32 mm what’s the area of the triangle
Ksju [112]

Answer:

4608*sqrt(3)

Step-by-step explanation:

x + 2x = 3x, so 3x is the height of the triangle.  This is a 90-60-30 triangle so the base would be 3x*sqrt(3).  To find the area, we can multiply the base with the height and divide by two, so it would be (3x)(3x*sqrt(3))/2 or (9/2)x^2 * sqrt(3).  x = 32, and plugging this into the equation gets us to (9/2)32^2 * sqrt(3), which is 4608*sqrt(3).  

6 0
3 years ago
Consider the equation 4x – 3y = 9. Write the equation in slope-intercept form, y = mx + b, and
Dafna1 [17]
Y=4/3x-3. Slope is 4/3
5 0
3 years ago
Find the surface area of the composite solid. Round your answer to the nearest hundredth. A. 178.04 cm2 B. 184.04 cm2 C. 187.08
Rashid [163]
I belive the answer is d I think I am studying the same thing also
8 0
3 years ago
Read 2 more answers
Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2
MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

The given line has a slope m1=5, thus the slope of our required line is:

\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}

The equation of the line now can be expressed as:

\displaystyle y=-\frac{1}{5}x+b

We need to find the value of b, which can be done by using the point (7,2):

\displaystyle 2=-\frac{1}{5}*7+b

Operating:

\displaystyle 2=-\frac{7}{5}+b

Multiplying by 5:

10=-7+5b

Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

7 0
3 years ago
What number must be added to 15,-6, and 12 to have a mean of 5? Explain.
Genrish500 [490]

You need to add a -1

We can find this by setting up the equation like so

x + (-6) + 12 + 15 / 4 = 5

x + 21 = 20

x = 20 -21

x = -1

Now if we insert -1 where x is located in the equation, you will get a means of 5

3 0
3 years ago
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