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sp2606 [1]
4 years ago
13

Which function will have a y-intercept at –1 and an amplitude of 2?

Mathematics
2 answers:
Artyom0805 [142]4 years ago
5 0

Answer:

B

Step-by-step explanation:

edge2020 quiz

Angelina_Jolie [31]4 years ago
4 0

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

h(x)=A\sin (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

The general form of cosine function

h(x)=A\cos (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

In function, f(x)=-\sin x-1

Amplitude : |A|=1

y-intercept : -1

In function, f(x)=-2\sin x-1

Amplitude : |A|=2

y-intercept : -1

In function, f(x)=-\cos x

Amplitude : |A|=1

y-intercept : 0

In function, f(x)=-2\cos x-1

Amplitude : |A|=2

y-intercept : -1

Therefore, the correct options are B and D.

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Write 257% as decimal
SCORPION-xisa [38]

Answer:

<u><em>please mark brainliest!</em></u>

Step-by-step explanation:

2.57

5 0
4 years ago
Read 2 more answers
Jeremy has 50 ft of fencing to enclose a rectangular-pen for his dog. He plans on using a side of his house for one side of the
kotykmax [81]

The dimensions such as length is 18 and width is 16 or length is 32 and width is 9 will produce an enclosed area of 288ft.

<h3>What is the dimension of length and width?</h3>

We know that,

P = l + 2w

50 = l + 2w

50 - 2w = l

A = l x w

288 = (50 - 2w)w

288 = 50w -2w²

2w² - 50w + 288

By dividing throughout by 2

w² - 25w + 144

This is in quadratic equation form.

By applying quadratic formula,

w = (-(-25) ± \sqrt{(-25)^{2}-4*1*144) / 2

w = (-(-25) ± 7)/2

w1 =  (-(-25) + 7)/2

w1 = (25 + 7) / 2

w1 = 16

w2 =  (-(-25) - 7)/2

w2 = (25 - 7) / 2

w2 = 9

By substituting the values in eq1,

A = l x w

if w = 16

288 = l x 16

l = 288/16

l = 18

if w = 9

288 = l x 9

l = 288/9

l = 32

The dimensions will be length is 18 and width is 16 or length is 32 and width is 9.

To learn more about area of rectangle refer to :

brainly.com/question/25292087

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3 0
1 year ago
The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in in
Grace [21]

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2,  76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

                             P.Q.  =  \frac{(n-1) \times s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s = sample standard deviation = \sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} } = 5.063

            \sigma = population standard deviation

            n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

<u>So, 90% confidence interval for the population standard deviation, </u>\sigma<u> is ;</u>

P(11.59 < \chi^{2}__2_1 < 32.67) = 0.90  {As the critical value of chi at 21 degrees  

                                                  of freedom are 11.59 & 32.67}  

P(11.59 < \frac{(n-1) \times s^{2} }{\sigma^{2} } < 32.67) = 0.90

P( \frac{ 11.59}{(n-1) \times s^{2}} < \frac{1}{\sigma^{2} } < \frac{ 32.67}{(n-1) \times s^{2}} ) = 0.90

P( \frac{(n-1) \times s^{2} }{32.67 } < \sigma^{2} < \frac{(n-1) \times s^{2} }{11.59 } ) = 0.90

<u>90% confidence interval for</u> \sigma^{2} = [ \frac{(n-1) \times s^{2} }{32.67 } , \frac{(n-1) \times s^{2} }{11.59 } ]

                                     = [ \frac{21 \times 5.063^{2}  }{32.67 } , \frac{21 \times 5.063^{2}  }{11.59 } ]

                                     = [16.48 , 46.45]

<u>90% confidence interval for</u> \sigma = [\sqrt{16.48} , \sqrt{46.45} ]

                                                 = [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

5 0
3 years ago
Please help with this
DIA [1.3K]
Sorry i cant see the picture so well
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3 years ago
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PLEASE HELP ASAP!!
Tasya [4]
Answer :
y + z = x


Plz mark me as brainliest
3 0
3 years ago
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