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shusha [124]
3 years ago
11

What is the mean of 7 and 38

alt="7 \sqrt{38} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0

Answer:

The mean of 7 and 38 is 22.5.

Step-by-step explanation:

Mean: Mean the average of the numbers or in other words it is the sum of numbers divided by the count.

Here the numbers are 7 and 38 and the count is 2

therefore,

\textrm{Mean of 7 and 38} = \frac{Sum}{Count} \\= \frac{7+38}{2} \\= \frac{45}{2}\\ = 22.5

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Answer:

1)-n-5m

2)-13n+10m+6mn

Step-by-step explanation:

1) (6n-7n)-5m= -n-5m

2)(n-7n-7n)+(2m+2m+6m)+6mn= -13n+10m+6mn

5 0
3 years ago
Solve equation using SQAURE ROOTS, show work. Round to the nearest hundredth if needed
ivann1987 [24]

Answer:

x=8, x=4

Step-by-step explanation:

<u>Add 4 to both sides</u>

(x-6)^2=4

<u>Square root</u>

<u />(x-6)= \sqrt{4}

x - 6 = ±2

x = 8

OR x = 4

So, x=8 or x=4

<u />

7 0
2 years ago
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UkoKoshka [18]

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3 0
3 years ago
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alukav5142 [94]
The answer is a. Irrationally numbers, when written as decimal numbers do not terminate nor do they repeat
6 0
3 years ago
at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t
baherus [9]

The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
So, we have P(S)=\frac{42}{100}=0.42, P(D)=\frac{25}{100}=0.25, P(S\cup D)=\frac{53}{100}=0.53.

We want to find the probability that a student participates in both sports and drama i.e., we want to find P(S\cap D).

By the above formula, we obtain:

P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}

Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0
2 years ago
Read 2 more answers
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