The pairs of angles<span> on one side of the transversal but inside the two lines are called </span>сonsecutive interior angles<span>.
</span>∠6 and ∠1
∠7 and ∠4
<span>
С and D options.</span>
Answer:
enlargement
Step-by-step explanation:
ABC is original
A'B'C' is that shape after a dilation
it became bigger, so its an enlargement
<span>–12 – 3 + 9
(-12 - 3) + 9
-15 + 9
-6</span>
Answer: y= -5x - 1
y = -5.2 + 7
Step-by-step explanation: y= -5x - 1 has 3. y = -5.2 + 7 has 1
Answer:

Step-by-step explanation:
Given
y = 3x + 1
Required
Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1
First, the slope of the line has to be calculated;
Th slope of a line is the coefficient of x in its linear equation;
This implies that the slope of y = 3x + 1 is 3
Having calculated the slope of the first line;
The relationship between both lines are perpendicularity; this implies that 
Where m_1 = 3 and m_2 is the slope of the secodnd line
becomes

Divide both sides by 3


The equation of the line can be calculated using the folloing formula

Where
and 
The equation becomes


Cross multiply


Collect like terms


