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4 years ago

Which expression gives the distance between points (1,-2) and (2,4)

Mathematics

1 answer:

Sauron [17]4 years ago

3 0

Answer:

$\sqrt{37}$

Step-by-step explanation:

Distance formula

$d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$

$d = \sqrt {\left( {1 - 2 } \right)^2 + \left( {-2 - 4 } \right)^2 }$

Simplify

$d = \sqrt {\left( {-1 } \right)^2 + \left( {-6 } \right)^2 }$

Simplify

$d = \sqrt {\left 1 + \left 36}$

$d = \sqrt{37}$

Answer

$d = \sqrt{37}$

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Find the solution to 1/4x +6 < 2 where the answer is x<-16

Novay_Z [31]

Answer:

x<-16

Step-by-step explanation:

1/4x+6<2

1/4x<2-6

1/4x<-4

x<-4/(1/4)

x<-4(4/1)

x<-16/1

x<-16

3 0

3 years ago

Will give brainliest

hoa [83]

Answer:

3,1,2

Step-by-step explanation:

I think it is 3,1,2 but I'm not completely sure lmk if it's correct or incorrect

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6 0

3 years ago

Please help me with number 9-10

Finger [1]

(10). 423,,,,,,,,,,4.10=40.. Hopefully that's help u

7 0

3 years ago

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

vampirchik [111]

<h2>Question:-</h2>

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

<h2>Solution:-</h2>

The age of Sita = (x + 5) years.

And, the age of Gautam = x years.

Now,

5 years ago, the ratio of their ages was 3 : 2

$\therefore$ $\bf \frac{3}{2} \: = \frac{x \: + \: 5}{x}$

Now by cross multiplying, we get,

3x = 2(x + 5)

3x = 2x + 10

3x - 2x = 10

Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.

And, the age of Gautam = x = 10 years.

Now,

The present age of Sita = 15 + 5 = 20 years. (Answer)

And, the present age of Gautam = 10 + 5 = 15 years. (Answer)

4 0

3 years ago

Factor completely. 150m^2nz+20mn^2c-120m^2nc-25mn^2z

Anika [276]

Answer:

The factor form is:

$5mn\left(6m-n\right)\left(5z-4c\right)$

Step-by-step explanation:

Here we have to find the factor of the expression:

$150m^2nz+20mn^2c-120m^2nc-25mn^2z$

So we need to take out the common terms, as we do for finding the greatest common factors.

Now the expression that is given can be re-written as:

$150m^2nz+20mn^2c-120m^2nc-25mn^2z\\=150mmnz+20mnnc-120mmnc-25mnnz\\=30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz$

Next, we will find the common terms, as follows;

$30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz\\=5nm\left(30mz+4nc-24mc-5nz\right)\\$

Now we will factorise the expression:

$\left(30mz+4nc-24mc-5nz\right)\\$

as follows;

$\left(30mz+4nc-24mc-5nz\right)\\=6m\left(5z-4c\right)+n\left(4c-5z\right)\\=\left(-4c+5z\right)\left(6m-n\right)\\$

So the final factor form is:

$150m^2nz+20mn^2c-120m^2nc-25mn^2z=5mn\left(6m-n\right)\left(5z-4c\right)$

8 0

3 years ago