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Cloud [144]
3 years ago
6

The daily low temperature in Guangzhou, China Varies over time in a periodic way that can be modeled by a trigonometric function

. The period of change is exactly one year. the temperature peaks around July 26 at 78°F and has its minimum half a year later at 49°F. assuming a year is exactly 365 days July 26 is 206/365 of a year after January 1. Find the formula of the trigonometric function that models the daily low temperature T in Guangzhou t years after January 1, 2015 defined the function using radians

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:

  T(t) = 14.5cos(2π(t -206/365)) +63.5

Step-by-step explanation:

The function can be written as ...

  T = A·cos(2π(t -206/365)) +B

where A is half the difference of the high and low temperature values, and B is the average of the high and low temperature values.

  A = (78-49)/2 = 29/2 = 14.5

  B = (78 +49)/2 = 127/2 = 63.5

The value 206/365 is the horizontal right shift of the peak of the function. That makes the peak occur on July 26, as required.

Filling in these values gives us the function ...

  T(t) = 14.5cos(2π(t -206/365)) +63.5

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a 1ft long piece of wire needs to be divided into two pieces which will form the shape of a circle and a square. Determine the l
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Length of wire for circle is 0.44 ft

Length of wire for square is 0.56 ft

Step-by-step explanation:

Let x is circumference of the circle

then

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a =  π(x/2π)^2

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a =  x^2/4π

Find the area of the square:

a =  (1-x/4)^2

a =  (1-2x+x^2)/16

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A =  (x^2/4π)+(1-2x+x^2/16)

A = 4x^2+3.142-6.284x+3.142x^2

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Find the axis of symmetry [x = -b/(2a)]

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3 years ago
How many different 10 person committees can be selected from a pool of 23 people?
Salsk061 [2.6K]

We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.

We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.

Formula for combination:

C(n,r)=\dfrac{n!}{(n-r)!r!}

Where n represents the number of objects/people in the set and r represents the number of objects/people being chosen from the set

There are 23 people in the set and 10 people being chosen from the set

C(23,10)=\dfrac{23!}{(23-10)!10!}

=\dfrac{23!}{13!\times10!}

Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

=1,144,066

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!

~ Padoru

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