4 cm squared because you count the whole shaded squares and add up the halves.
Answer:the sale of a product increases at first then decreases.
Step-by-step explanation:
Answer:
Part 1) Helen's age is 32 years old and Jane's age is 24 years old
Part 2) 13 twenty-dollar bills
Step-by-step explanation:
Part 1) Helen is 8 years older than Jane. Twenty years ago Helen was three times as old as Jane. How old is each now and what is the equation?
Let
x----> Helen's age
y---> Jane's age
we know that
x=y+8 ----> equation A
(x-20)=3(y-20) -----> equation B
substitute equation A in equation B and solve for y
(y+8-20)=3(y-20)
y-12=3y-60
3y-y=60-12
2y=48
y=24 years
Find the value of x
x=y+8
x=24+8=32 years
Part 2)
Let
x-----> the number of five-dollar bills
y----> the number of twenty-dollar bills
we know that
5x+20y=305 -----> equation A
y=x+4 ------> x=y-4 ------> equation B
substitute equation B in equation A and solve for y
5(y-4)+20y=305
5y-20+20y=305
25y=325
y=13 twenty-dollar bills
Find the value of x
x=y-4
x=13-4=9 five-dollar bills
Answer:
Sol: In this question, firstly we have to make the first bracket as a complete square of the second bracket. This we can by adding 2.x.1/x which is equivalent to 2. Then the equation becomes:
6(x2 + 1/x2 +2) – 5(x + 1/x) = 50 { 38 + 6*2)
⇒ 6(x2 + 1/x2 +2) – 5(x + 1/x) – 50 = 0
Now put x + 1/x = y
⇒ 6y2 -5y -50 = 0
⇒ (2y +5)(3y-10)= 0
⇒ y=-5/2 or 10/3
As x is positive therefore, x + 1/x =10/3
On solving further you will get as x=3 or 1/3
So 1/9-16z^2 this is a diffirence of two perfect squares thing
so (1/3)^2-(4z)^2
so ((1/3)-4z)((1/3)+4z)
