A negative number raised to an exponent is positive. Which of the following is not true?

Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Ugo [173]

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

8 0

2 years ago

Plsi I’ll give brainless

Kay [80]

Answer:

It's below in the explanation

Explanation

1. x has to be greater than 2. So 3 and 4 both work

2. x has to be less than 22. So 21 and 20 both work

3. t has to be less than 5. So 3 and 4 both work

4. There isn't a number there. what is 5 less that?

5. j has to be less than 5 so 5 and 4 both work

6. y has to be less than 4. So 4 and 3 both work

7. B has to be greater than 26. so 26 27 and 28 all work

8.There isn't a number there

9.b can be 3 or greater than 3.

10.z can be 6 or greater than 6

Hope this Helps!

4 0

2 years ago

Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side

svp [43]

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6

Last, we have all the information needed in order to calculate the area by the formula:

$A = \frac{(AB + CD)DH}{2}$

A = (7 + 5) × 2√6 ÷ 2
= 12√6

The area of the regular trapezoid is 12√6 square units.

7 0

2 years ago

Holly made 12 pair of earrings for each of her girlfriends. To wrap the pairs individually, she creates a simple cardboard gift

Mekhanik [1.2K]

Answer:

3280cm²

Step-by-step explanation:

We are told the gift box is folded into a Pyramid with a square base.

Hence, we are to find the Surface Area of a square pyramid

From the question, we are given:

Length of the base of the square = 10cm

Triangle

Side length = 10cm

Height = 8 2/3 cm

A square Pyramid has 5 faces: 4 triangles and 1 square.

Step 1

Find the Area of the square

Formula = Side length² this is because all the side of a square is equal.

Length of the base = 10cm

Area of the square = (10cm)²

= 100cm²

Step 2

Find the Area of the triangle. We are told the 4 triangles are equilateral, which means their side are equal.

Hence, for one triangle.

Area of a triangle = 1/2 × base × height

Base = side length = 10cm

Height = 8 2/3 = 8.6666666667cm

Area of a triangle = 1/2 × 10 × 8.6666666667

Area of a triangle = 43.333333333cm²

Since we have 4 triangles

We would have : 4 × 43.333333333cm²

= 173.33333333cm²

The Area of the 4 equilateral triangles =

173.33333333cm²

Step 3

The Surface area of the Square Pyramid

= Sum of the areas of all the faces.

= 100cm² + 173.33333333cm²

= 273.33333333cm²

Therefore, the minimum amount of cardboard needed to make one gift box = 273.33333333cm²

Step 4

The minimum amount of cardboard Holly needs to create 12 gift boxes to wrap each pair of earrings individually is calculated as: 12 × 273.33333333cm²

= 3280cm²

7 0

2 years ago

CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?

sukhopar [10]

Answer:

Step-by-step explanation:

1.

$(c+9)^2=64=8^2\\$

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

D

2.

8x^2-3=2

8x^2=5

$x^2=\frac{5}{8}=\frac{10}{16}$

$x=±\frac{\sqrt{10}}{4}$

so A

3.

$x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}$

so D

or

8 0

2 years ago