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4 years ago

Is 12.89 irrational

1 answer:

7 0

No. It's the ratio of 1,289 to 100 .

Also, it can be written as a fraction with whole numbers
on top and bottom, like this: 1289 / 100 .

Also, it can be written down on paper completely, using
digits and a decimal point or fraction bar. (You did that.)

Any one of these three facts makes it a rational number.

You might be interested in

Given that f(x) = x^2 - 4x +1, find the value of m if f(m) = -3

iragen [17]

a. Answer: m = 2

Step-by-step explanation:

f(x) = x² - 4x + 1

f(m) = m² - 4m + 1 = -3

m² - 4m + 4 = 0

(m - 2)(m - 2) = 0

m = 2

***************************************************

b. Answer: k = 2 and k = 5

Step-by-step explanation:

f(x) = x² - 7x + 14

f(k) = k² - 7k + 14 = 4

k² - 7k + 10 = 0

(k - 2)(k - 5) = 0

k = 2 k = 5

3 0

3 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago

Please help out thanksssss yallllllll!!!!!!!!!

Mila [183]

Answer:

okyyyyyyyyyyyyyyyyyy

4 0

3 years ago

Read 2 more answers

Which of the following equations has a graph PARALLEL to the line y = 4x + 7

Kobotan [32]

Answer:

y = 4x - 2

Step-by-step explanation:

This equation has the same slope as the equation given which means that they are parallel lines. This equation also has a y-intercept of -2.

I graphed both equations below to show you that they are parallel.

If this answer is correct, please make me Brainliest!

4 0

3 years ago

Much help needed thank you

suter [353]

Answer:

14.29

Step-by-step explanation:

Let p be the price of the cd

we take the price of the cd plus the tax and it must be less than or equal to 15

the tax is the price of the cd times 5 %

p + p*.05 ≤15

Combine like terms

p*1.05 ≤15

Divide each side by 1.05

p ≤15/1.05

p ≤14.28571429

Rounding to the nearest cent

p ≤14.29

The maximum price is 14.29

7 0

3 years ago