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3 years ago

I’m practically begging someone please help me!!

Mathematics

1 answer:

Oliga [24]3 years ago

6 0

My guys is is not just (5, -10)?

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You want $5000 4 years from nowfor a down payment for a car. How much money must be deposited monetly into an account earning 4.

timama [110]

Answer:

$95.5090 must be deposited monthly

Step-by-step explanation:

From the information given:

The annual interest rate (r) = 4.2% = 0.042

Let assume that an amount Y is deposited, then after one month, it will increase to:

$Y ( 1+ \dfrac{0.042}{12})$

The total amount after 4 years will be:

$= Y ( 1+ \dfrac{0.042}{12})^{48}+Y ( 1+ \dfrac{0.042}{12})^{47} +Y ( 1+ \dfrac{0.042}{12})^{46} +...+ Y ( 1+ \dfrac{0.042}{12})$

$= Y ( 1.0035)^{48}+Y ( 1.0035)^{47} +Y( 1.0035)^{46} +...+ Y( 1.0035)$

Using the sum of a geometric progression:

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{(1.0035-1)}$

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035}$

The above amount is then equal to $5000

i.e

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035} = 5000$

$Y = \dfrac{5000\times 0.0035}{(1.0035)(1.0035^{48}-1)} \\ \\ \mathbf{Y = \$95.5090}$

8 0

3 years ago

Can someone help me please

antoniya [11.8K]

Answer:

Step-by-step explanation:

4 0

3 years ago

A university has 750 female students and 2250 male students. Thirty per cent of female students study chemistry and 60% of male

UNO [17]

Answer:

1/7 or 14.3%

Step-by-step explanation:

30% of 750 = 225 (females who study chemistry)

60% of 2250 = 1350 (males who study chemistry)

1575 = total students studying chemistry

P (female chemistry student) = 225/1575 = 1/7 (simplified)

1/7 = 14.3%

7 0

2 years ago

What is the answer to 35=-7=[z+8]

Ronch [10]

I believe you mean to put "()" not "[]"
I got <span>z = -8 as my answer
</span><span />

8 0

3 years ago

What is the amount of a $4,000.00 annuity due at 12 percent compounded semiannually for 3 years?

Dmitriy789 [7]

Answer:

$ 5674.076

Step-by-step explanation:

The question is on compound interest

The formulae = A= P(1+ r/n) ^nt .......where P is the principal amount, r is the rate of interest in decimal, n is number of compoundings per year and t is the total number of years.

Given; P= $4,000.00 , r=12/100=0.12, n=2 and t=3

Substituting values in the equation A= P(1+ r/n) ^nt

A= 4000 ( 1+0.12/2)^2×3

A=4000(1.06)^6

A=$ 5674.08

3 0

3 years ago