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Citrus2011 [14]
3 years ago
15

I’m practically begging someone please help me!!

Mathematics
1 answer:
Oliga [24]3 years ago
6 0
My guys is is not just (5, -10)?
You might be interested in
What is the equation?
pishuonlain [190]

Answer:

(x - 7)^2 + (y - 2)^2 = 5^2

Step-by-step explanation:

Center at (7, 2); radius 5

Adapt (x - h)^2 + (y - k)^2 = r^2 to this situation.  Replace h by 7, k by 2 and r by 5:

(x - 7)^2 + (y - 2)^2 = 5^2

3 0
3 years ago
Can someone plz help me with this question
Nostrana [21]
10^2 is 10×10 which is 100
4^2 is 4×4 which is 16
so it simplifies to 100-16×2. By Order Of Operations, parentheses, exponents, multiply and divide, add and subtract 100-16×2 makes 100-32 which is 68
5 0
3 years ago
In the right ΔABC, AN is the altitude to the hypotenuse. Find BN, AN, and AC, if AB=2√5 in and NC= 1 in.
kipiarov [429]

Answer:

BN=4\ \text{in}

AN=2\ \text{in}

AC=\sqrt{5}\ \text{in}

Step-by-step explanation:

Let BN=x

BC=c

NC=y=1\ \text{in}

AB=a=2\sqrt{5}\ \text{in}

AC=b

We have the relation

\dfrac{BC}{AB}=\dfrac{AB}{BN}\\\Rightarrow \dfrac{c}{a}=\dfrac{a}{x}\\\Rightarrow c=\dfrac{a^2}{x}\\\Rightarrow x+1=\dfrac{a^2}{x}\\\Rightarrow x^2+x=20\\\Rightarrow x^2+x-20=0\\\Rightarrow x=\frac{-1\pm \sqrt{1^2-4\times 1\times \left(-20\right)}}{2\times 1}\\\Rightarrow x=4,-5

\boldsymbol{BN=4\ \text{in}}

h=\sqrt{a^2-x^2}\\\Rightarrow h=\sqrt{(2\sqrt{5})^2-4^2}\\\Rightarrow h=2\ \text{in}

\boldsymbol{AN=2\ \text{in}}

b=\sqrt{h^2+y^2}\\\Rightarrow b=\sqrt{2^2+1^2}\\\Rightarrow b=\sqrt{5}\ \text{in}

\boldsymbol{AC=\sqrt{5}\ \text{in}}

8 0
3 years ago
Can one of you lovely people help me please ?
saveliy_v [14]

Answer:

the answer is

C. = x=22.82

4 0
3 years ago
Read 2 more answers
I NEEDDD HELPPPP ASAPPPP ITS URGENTTT!!!!
natulia [17]

Answer:

(x-6)^2+(y-14)^2=4

Step-by-step explanation:

7 0
3 years ago
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