0.375 L of the NaCl solution contains 0.455 moles (1)
since it was diluted to 1.88 L
then let 1.88 L of solution contain x moles (2)
by combining both (1) and (2)
⇒ (0.345 L) x = (0.455 mol) (1.88 L)
⇒ x = (0.242 mol · L) ÷ (0.345 L)
⇒ x = 0.702 mol
Thus the molarity of the NaCl after being diluted is 0.702 M OR 0.702 mol / L OR 0.702 mol/dm³.
Answer:
The hydrogen ion concentration in a solution, [H+], in mol L-1, can be calculated if the pH of the solution is known.
pH is defined as the negative logarithm (to base 10) of the hydrogen ion concentration in mol L-1 pH = -log10[H+] ...
[H+] in mol L-1 can be calculated using the equation (formula): [H+] = 10-pH
Answer:
Chemical Reactions. ... Reactions occur when two or more molecules interact and the molecules change. Bonds between atoms are broken and created to form new molecules.
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
