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Elanso [62]
3 years ago
5

Ions in a certain volume of 0.20MNaCl(aq) are represented in the box above on the left. In the box above on the right, draw a pa

rticulate diagram that represents the ions in the same volume of 0.10MCaCl2

Chemistry
2 answers:
jonny [76]3 years ago
8 0

Answer:

Four Ca²⁺ and eight Cl⁻ ions.  

Explanation:

If

0.20 mol·L⁻¹ NaCl =  8Na⁺ + 8Cl⁻

Then

0.10 mol·L⁻¹ NaCl =  4Na⁺ + 4Cl⁻

And

0.10 mol·L⁻¹ CaCl₂ = 4Ca²⁺ + 8Cl⁻

The square will contain 4 Ca²⁺ ions and 8 Cl⁻ ions.

It should resemble the diagram below

Diano4ka-milaya [45]3 years ago
5 0

Answer:

Explanation:

Find attached solution

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Rearrange the elements in the order of increasing first ionization energy. Place the element symbol with the lowest first ioniza
Nastasia [14]

Answer:

I,Br,Cl,F

Explanation:

ionization energy decreases the farther down an element is

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Part A Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a ch
Basile [38]

Answer:

2HNO3+Ca(OH)2 = Ca(NO3)2+2H2O

Explanation:

The reaction between Nitric acid(HNO3)and Calcium hydroxide(Ca(OH)2) gives Calcium Nitrate( Ca(NO3)2 and Water( H2O)

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How is a crystal different from a solid made of individual molecules
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In a crystal, the molecules are closer together as they are in any solid. they have less room to move, and might even be combined together rather than individual

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3 years ago
Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What
Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For CH_4  :-

Mass of CH_4  = 1.28 g

Molar mass of CH_4  = 16.04 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.28\ g}{16.04\ g/mol}

Moles_{CH_4}= 0.0798\ mol

For O_2  :-

Mass of O_2  = 10.1 g

Molar mass of O_2  = 31.998 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{10.1\ g}{31.998\ g/mol}

Moles_{O_2}= 0.3156\ mol

According to the given reaction:

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, CH_4 is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0798\ moles= \frac{Mass}{44.01\ g/mol}

Mass of CO_2 = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0
3 years ago
Chemical formula of ammonium oxide
11111nata11111 [884]

The answer is (NH4)2O

8 0
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