I think your answer should be 2.8 g
Answer: The enthalpy of reaction is, -206.18 kJ
Explanation:-
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The final reaction is
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now adding (2) and (3) and subtracting (1) , we get :
Therefore, the enthalpy of reaction is, -206.18 kJ
The correct answer is option C, that is, hypothesis.
The hypothesis is the starting building block in the scientific method. It is also illustrated as an educated guess, based on previous observation and knowledge. A hypothesis refers to a recommended solution for an unexplained event, which does not fit into the present accepted scientific theory.
The fundamental concept of a hypothesis is that there is no pre-determined result. For a hypothesis to be considered as scientific hypothesis, it has to be something, which can be refuted or supported via carefully crafted observation or experimentation.
Answer:
2m/s²
Explanation:
When an object starts or at its state of rest it has an Initial speed U = 0
Final speed = 6m/s
total time taken for the acceleration = 3s
Acceleration =?
Acceleration is the change in velocity (speed) with time
OR
Time rate of change of velocity
Acceleration = <u>Change in Speed(velocity)</u>
Time taken
Hence,
Acceleration = <u> </u><u> </u><u>V - </u><u>U</u><u> </u><u> </u>
t
a = <u>6</u><u> </u><u>-</u><u> </u><u>0</u>
3
a = <u>6</u><u> </u><u> </u>
3
a = 2m/s²
<h3><u>Answer; </u></h3>
=10.38 moles KOH
<h3><u>Explanation</u>;</h3>
The balanced equation.
6KOH + Al2(SO4)3 --> 3K2SO4 + 2Al(OH)3
From the equation;
1 mole of aluminum sulfate requires 6 moles of potassium hydroxide.
Moles of Aluminium sulfate; 1.73 moles
Moles of KOH;
1 mol Al2(SO4)3 : 6 mol KOH = 1.73 mol Al2(SO4)3 : x mol KOH
Thus; x = (6 × 1.73)
<u> =10.38 moles KOH </u>
