If we place 0 and 1 for the x then:

this is the line:
Answer:
1:
<A=½(arcJL)=½(70+120)=35+60=95°
[inscribed angle is half of central angle]
2:
<W=½arcVX=½(130)=65°
[inscribed angle is half of central angle]
3.
<E=½(arcDC)=½(90)=45°
[inscribed angle is half of central angle]
4.
<R=½(arcXZ)=½(110+62)=86°
[inscribed angle is half of central angle]
5.
<B=½(arc DC)=½×104°=52°
[inscribed angle is half of central angle]
6.
<K=90°
[inscribed angle in a diameter is complementary]
<K+<J+<L=180°(sum of interior angle of a triangle]
<L=180°-90°-53°=37°
again
arc JK=2×<L=2×37=74°
Answer:
i
Step-by-step explanation:
Answer:

Step-by-step explanation:
We have to arrange the functions given in ascending order which have eventually the least value and eventually the greatest value.
So, we get the following table representing the values of the functions for different values of x.
x : 5 10 15
: 23 38 53
: 1027 1048579 1073741827
: 31 106 231
: 15 30 45
: 1024 1048576 1073741824
: 25 100 225
As, can be seen from the table that the ascending order of the functions is given by
.
Hence, the order is
.
Answer:
48.8 lbs
Step-by-step explanation:
The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:
a/sin(A) = c/sin(C)
x/sin(26°) = 80/sin(134°)
x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds
The larger component force is about 48.8 pounds.