Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
Answer:
4 is b 0.15
i think 5 is b
Step-by-step explanation:
i couldn't figure out the others "-u-
The answer is 56.8
explaination:14.2 x4
56.8
he needs five units he already have 1 unit
so5 minus 4=one
so....
14.2x4=56.8//
Step-by-step explanation:
Solution:
(a) is the vertical direction, the force of gravity
on the object (or the wight force: w = Mg ) pulls the crate down while the surface reaction. N. pushes it 103N
rd, as shown:
w = Mg = (20.0kg 9.8m s3 - 196N
N- 196N as well
(b) In the horizontal direction, in the absence of
friction, there are two forces: (F) and the 53-N force. Applying the Newton's 2nd law helps the calculation of the unknown force. F. F - 53N (20.0 kg)(2.5 m 3
F = 103N plz mark me as brainliest
Answer:
Step-by-step explanation:
