The measures of the angles between the resultant and two applied forces are 26° and
1 answer:
Answer:
48.8 lbs
Step-by-step explanation:
The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:
a/sin(A) = c/sin(C)
x/sin(26°) = 80/sin(134°)
x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds
The larger component force is about 48.8 pounds.
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CHECK THE ATTACHED FIQURE FOR THE BRIDGE
Answer:
60 ft
Step-by-step explanation:
From the question we know that triangles ABC and EDC are in a 1:1 with this given ratio it implies that
triangles ABC and EDC are congruent then we can say
side EC = side AC
3x + 9 = 5x - 5
Then we can simplify to know value of x
3x + 14= 5x
2x = 14
x = 7
But we know that AC= 5x - 5 , then substitute value of x into it
AC = 5x + 5 = 5(7) - 5
= 35 - 5
AC= 30 ft
Also EC= 3x + 9 then substitute value of x into it
EC = 3x + 9 = 3(7) + 9
= 21 + 9
EC= 30 ft
Then the the distance between the top and bottom of the bridge, in feet, = EC+AC
= 30 + 30 = 60 ft
