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Fed [463]
3 years ago
11

A^2-b^2 a^2b-ab^2-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

\huge{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}

Step-by-step explanation:

\huge{ \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b}  +  {ab}^{2}  }  \div  \frac{ {a}^{2b} -  {ab}^{2}  }{ {a}^{2b} -  {ab}^{2}  }}

\huge{\frac{ {x}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }  \div 1}

\huge{\boxed{\green{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}}}

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Leon has a gift card for $100. He spent $65 of it on books. What is the new balance in Leon's card?
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Answer:

$35

Step-by-step explanation:

Please mark brainliest

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3 years ago
What is the solution to the system of equations?
Butoxors [25]

Answer:

y=2/3

y=4

x=1

Step-by-step explanation:

y=2/3

y=x+3

x= -2x+3

x+2x=3

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4 0
3 years ago
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Will mark brainliest!!!<br> Solve for x and plz do both
sladkih [1.3K]

Answer:

8. 64.23

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7 0
3 years ago
I need help solving this
Stolb23 [73]

Step-by-step explanation:

So in the equation given, y = 2x - 3

you substitute x for whats given in the table in the x column.

Example

In the graph the first number under the x colum is -1.

y = 2x - 3 in the equation you take out x and put -1.

So now the equation becomes y = 2 × -1 - 3.

Using bedmas to solve the question you should get -5

Which now means y = -5

To plot the point now x would be -1 and y would be -5 (-1, -5)

Same thing for the second number in the x Column.

y = 2 × 1 - 3 which equals -1

To plot it

x = 1 y = -1. (1, -1)

And for the last number 3.

Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3

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4 0
3 years ago
Convert 22 to a numeral in base 2.
musickatia [10]
The answer is 10110

===============================================

Explanation:

Divide 22 over 2. Use long division to find the quotient and remainder
22/2 = 11 remainder 0 <<--- this remainder will be used later. Call it A, so A = 0

Now repeat for the value 11, which was the quotient above
11/2 = 5 remainder 1 <<--- this remainder will be used later. Call it B, so B = 1

Repeat again for the quotient we just got
5/2 = 2 remainder 1 <<--- this remainder will be used later. Call it C, so C = 1

Repeat again
2/2 = 1 remainder 0 <<--- this remainder will be used later. Call it D, so D = 0

Repeat again
1/2 = 0 remainder 1 <<--- this remainder will be used later. Call it E, so E = 1

The last quotient above is 0, so we stop here. If we tried to keep going, then we'd get nothing but 0 remainders forever.

The remainders we got above were:
A = 0
B = 1
C = 1
D = 0
E = 1

The idea is to read the remainders in reverse order in which we found. So we start with E and work back to A
E = 1
D = 0
C = 1
B = 1
A = 0

So 22 base 10 = 10110 base 2

5 0
3 years ago
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