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3 years ago

A^2-b^2 a^2b-ab^2-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2

Mathematics

1 answer:

Damm [24]3 years ago

5 0

Answer:

$\huge{= \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} }}$

Step-by-step explanation:

$\huge{ \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} } \div \frac{ {a}^{2b} - {ab}^{2} }{ {a}^{2b} - {ab}^{2} }}$

$\huge{\frac{ {x}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} } \div 1}$

$\huge{\boxed{\green{= \frac{ {a}^{2} - {b}^{2} }{ {a}^{2b} + {ab}^{2} }}}}$

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A^2-b^2 a^2b-ab^2-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​

A^2-b^2 a^2b-ab^2-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2