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Fed [463]
3 years ago
11

A^2-b^2 a^2b-ab^2-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

\huge{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}

Step-by-step explanation:

\huge{ \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b}  +  {ab}^{2}  }  \div  \frac{ {a}^{2b} -  {ab}^{2}  }{ {a}^{2b} -  {ab}^{2}  }}

\huge{\frac{ {x}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }  \div 1}

\huge{\boxed{\green{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}}}

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Consider the radical equation VC+22 = c + 2. Which statement is true about the solutions c = 3 and c =-6?
dangina [55]

36

Step-by-step explanation:

6 0
3 years ago
The product of 6 and the quantity 9 more then the number x is 253​
allochka39001 [22]

Answer:

6(x+9)=253

Step-by-step explanation:

we know that

The algebraic expression of the phrase"The product of 6 and the quantity 9 more then the number x is 253" is equal to the number 6 multiplied by the sum of x and 9 and this result is equal to 253

so

6(x+9)=253

solve for x

6x+54=253

6x=253-54

6x=199

x=199/6

3 0
4 years ago
A humpback whale swims at 40mph for 30 minutes, then rests for 15 minutes, then swims at 32 mph for 45 minutes. What is the whal
klasskru [66]
Average speed=totaldistance/ttoaltime

d=rt
40mph for 30mins (1/2 hr), travels 20mi
rest for 15min (1/4 hr), travels 0mi
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total distance=20+0+24=44
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44/(3/2)=44 times 2/3=88/3=29 and 1/3

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6 0
3 years ago
Read 2 more answers
I NEED HELP WITH THIS! ANYONE???
Aneli [31]

Answer:

y-axis, x-axis, y-axis, x-axis

Step-by-step explanation:

Alright, so this problem looks a lot harder than it really is. When you flip a point across the x axis, y becomes negative, and when it is flipped across the y axis, x becomes negative. This means that if the x value changes signs it was flipped on the y axis, and vice versa.

3 0
3 years ago
HELP “The vertical supports in this truss bridge are built so that
ElenaW [278]

Answer:

The statement that is not true is;

c) m∠ABO = m∠ODC

Step-by-step explanation:

With the assumption that the lengths AO, and OD are equal, we have that in ΔABO and ΔOCD, the following sides are corresponding sides;

Segment AO on ΔABO is a corresponding side to segment OD on ΔOCD

Vertices B and C on ΔABO and ΔOCD are corresponding vertices

Therefore;

Segments AB and OB on ΔABO are corresponding sides to segments OC and OD on ΔOCD respectively

Therefore, ∠ABO on ΔABO is the corresponding angle to ∠OCD on ΔOCD

Given that ΔABO ≅ ΔOCD, we have that ∠ABO ≅ ∠OCD

Therefore;

m∠ABO = m∠OCD by definition of congruency

5 0
3 years ago
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