Even numbers on die: 2,4,6odd numbers on die: 1,3,5 3+3=6 -> 6 numbers in total3/6 chance because there are 3 even numbers. This would round to 1/2, so 1/2
Number 7: 11/12-9/10 = 110/120-108/120=2/120= 1/60
number 8: 5/18-1/3=15/54-5/54=10/54 =5/27
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Answer:</h2>

<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable
which is the smaller number. Accordingly, the lager number will be
given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

So:
1. The sum of 2 consecutive integers can be written as:

2. Nine times the smaller and 5 times the larger can be written as:

Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:


The two numbers are:
