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3 years ago

A bottle of body wash costs 2.88 and contains 12 ounces. How much does it cost per ounces?

1 answer:

3 0

$2.88/12 = $0.24 per ounce of body wash
This can be solved by using a calculator.
Hope this helps!

You might be interested in

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes o

spayn [35]

Answer: There are 32 students who like brussels sprouts but dislike beans.

Step-by-step explanation:

Since we have given that

Number of students eat in the cafeteria = 120

Fraction dislike lime beans = $\dfrac{2}{3}$

Fraction who dislike lime beans and brussles sprouts both = $\dfrac{2}{3}\times \dfrac{3}{5}$

Fraction who dislikes lime beans but not brussles is given by

$\dfrac{2}{3}(1-\dfrac{3}{5})\\\\=\dfrac{2}{3}\times \dfrac{2}{5}\\\\=\dfrac{4}{15}$

So, Number of students who like brussels sprouts but dislike lima beans is given by

$\dfrac{4}{15}\times 120\\\\=32$

Hence, there are 32 students who like brussels sprouts but dislike beans.

7 0

3 years ago

What is the value of x? 45° ( 2x-5)°

AlekseyPX

(2x - 5)° + 45° = 180°

2x° + (-5 + 45)° = 180°

2x° + 40° = 180°

2x° = 180° - 40°

2x° = 140°

x° = 140 ÷ 2

x° = 70°

So, the value of x is 70°

Hope it helps and is useful :)

5 0

3 years ago

Read 2 more answers

1 3/4 * 2 1/2 pleas help

Nastasia [14]

Answer:

35/8 if its simple multiple then

Step-by-step explanation:

7/4*5/2

35/8

3 0

3 years ago

Read 2 more answers

Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am

Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

6 0

3 years ago

A baker sells cookies for 1.5 each. If a minimum of two dozen cookies is ordered

topjm [15]

36.00 that is the answer

3 0

3 years ago