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solong [7]
3 years ago
8

how many 5 card poker hands consisting of 2 aces and 3 kings are possible with an ordinary 52 card deck

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0
2 aces can be selected from 4 aces by 4C2 = 4!/2!(4 - 2)! =4!/ (2! x 2!) = (4 x 3 x 2 x 1)/(2 x 1 x 2 x 1) = 6 ways
3 kings can be selected from 4 kings by 4C3 = 4!/3!(4 - 3)! =4!/ (3! x 1!) = (4 x 3 x 2 x 1)/(3 x 2 x 1 x 1) = 4 ways

Therefore, the number of <span>5 card poker hands consisting of 2 aces and 3 kings possible with an ordinary 52 card deck is 6 x 4 = 24</span>
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bazaltina [42]

Answer:

C 1/125

Step-by-step explanation:

5  ^−3

Calculate 5 to the power of −3 and get  

1/125

​

​

7 0
2 years ago
If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices
kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Where det(A) = ad - bc # 0 so A is nonsingular:

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A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Then the inverted version of transposed A is

(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

The inverted version of A is:

A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]

The transposed version of inverted A is:

(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

We can see that

(A^T)^{-1} = (A^{-1})^T

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3 0
3 years ago
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zhenek [66]
207,048 is the answer :)
3 0
3 years ago
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Natasha2012 [34]

Answer:

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The range is the difference between the largest value in the date minus the smallest value in the data.

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8 0
3 years ago
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