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Olin [163]
3 years ago
5

Which of the following ordered pairs

Mathematics
2 answers:
nata0808 [166]3 years ago
6 0

Answer:

D

Step-by-step explanation:

y= 5x

10= 5(2)

10=10

FromTheMoon [43]3 years ago
4 0

Answer:

D

Step-by-step explanation:

To solve this you can just plug in the x values into the equation and if the answer is correct the y value should be your answer

For example if we look at D

we can plug in 2 for y=5x and get 10

We can see that the y value in the ordered pair is also 10 making this the correct answer

kind of hard to explain if you have any questions leave a comment

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Terry has 25 bills. He has ten-dollar bills and fifty-dollar bills
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Answer: He can have 12 fifty-dollars bills and 7 ten-dollar bills.

Step-by-step explanation:

12*50=700

7*10=70

      _____+

       770

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4 years ago
A baby girl weighed 18 lb 10 oz at 11 months and 20 lb 2 oz at 12 months. How much weight did the baby gain during this month?
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Answer:

B

Step-by-step explanation:

6 oz, 19lb

1 lb, 20lb

2 oz, 20lb 2oz

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4 0
3 years ago
-13/10x - 3/2 (11/6x +1)
lukranit [14]
So first simplify 11/6x into 11x/6. Then -13/10x into -13x/10. So you should now have (-13x/10-11x/4)-3/2. Combine the like terms -13x/10 and -11x/4 to get -81x/20 and then with your left over -3/2= -81x/20-3/2
4 0
3 years ago
A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).
likoan [24]

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

8 0
4 years ago
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