Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer:
he started with either 20 or 15 i probably thought about this way to much so this is the best i could come up with
Step-by-step explanation:
ITS C - Factor 6 out of the variable terms
If you break it up:
Three-eighths = 3/8
Sixteen times a number, we'll call the unknown number X, so 16X.
Twenty Four = 24
The sum of 16X and 24 = 16X + 24
We want 3/8 of that sum so we put the sum in parenthesis and we get:
Y = 3/8(16X + 24) where Y is the answer youd get if you knew what X was.
Answer:
that is scientifically impossible
Step-by-step explanation:
one you can't add, subtract, round up, or use decimals write that down.
