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leonid [27]
3 years ago
6

Adenosine triphosphate (ATP) is the main energy currency used in cells. ATP hydrolysis is coupled with unfavorable reactions, ma

king the net change in energy for the set of reactions less than 0, which is favorable. Although ATP is the main energy currency, other molecules can fulfill this role and take part in coupled reactions. Determine whether each of the phrases or examples describes a thioester, reduced cofactor, or phosphorylated compound.Acetyl COA, Ubiquinol, Phosphocreatine, the Sulfur-Carbon bond is hydrolyzed, These compounds yield H2P04- upon hydrolysis, These compounds accept e- during the oxidation of substrates and energy is released when they are oxidized. Please sort those phrases under "thioester," "reduced cofactor," or "phosphorylated compound," and explain why for each choice!
Chemistry
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

<em>Thioesters- the Sulfur-Carbon bond is hydrolyzed, e.g. AcetylCoA</em>

<em>Reduced cofactor- These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized, e.g. Ubiquinol</em>

<em>Phosphorylated compounds- These compounds yield H₂P0₄⁻ upon hydrolysis, e.g. Phosphocreatine</em>

Explanation:

<em>Thioesters</em><em> are esters in which the linking oxygen atom is replaced by a sulphur atom. </em>They are the product of esterification between a carboxylic acid and a sulfhydryl group (thiol). They have the functional group R–S–CO–R'. Thioesters are common intermediates in many biosynthetic reactions. Examples include malonyl-CoA, acetyl-CoA, and propionyl-CoA. <em>In the hydrolysis of thioesters, the sulfur-carbon bond is hydrolyzed.</em>

<em>Cofactors</em><em> can be either organic or inorganic molecules that are required by enzymes to function. Cofactors can be oxidized or reduced for the enzymes to catalyze the reactions.</em>  Examples include, NAD, FAD, NADP, <em>Coenzyme Q₁₀.</em> Coenzyme Q₁₀ exists in three redox states, fully oxidized, partially reduced, and fully reduced. Ubiquinol is the reduced (electron-rich) form of coenzyme Q₁₀. Coenzyme Q₁₀ is vital for proper transfer of electrons within the mitochondrial oxidative respiratory chain, whose main function is to produce adenosine triphosphate (ATP). <em>These compounds accept electrons during the oxidation of substrates and energy is released when they are oxidized. </em>

Phosphorylated compounds are compounds with a phosphoryl group (PO₃²⁻) attached to its molecules. <em>These compounds yield an inorganic phosphate (H₂P0₄⁻) upon hydrolysis</em>. Phosphorylation is especially important for protein function as this modification activates or deactivates almost half of the enzymes, thereby regulating their function. Examples include, glucose-1-phosphate, phosphoserine, phosphocreatine, etc.

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4.00 moles of CU(CN)2<br><br>Find the number of grams ​
UNO [17]

Hey there!

Cu(CN)₂

Find the molar mass.

Cu: 1 x 63.546 = 63.546

C: 2 x 12.01 = 24.02

N: 2 x 14.07 = 28.14

-----------------------------------

                      115.706 grams

The mass of one mole of Cu(CN)₂ is 115.706 grams.

We have 4 moles.

115.706 x 4 = 463

4.00 moles of Cu(CN)₂ has a mass of 463 grams.

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3 years ago
For each of the following compounds, write the symbols of the ions in the compound, and the number of each ion in the molecule o
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8 0
3 years ago
Consider the reaction directly below and answer parts a and b. C6H4(OH)2 (l) + H2O2 (l) à C6H4O2 (l) + 2 H2O (l)
dedylja [7]

Answer:

a. -206,4kJ

b. Surroundings will gain heat.

c. -115kJ are given off.

Explanation:

It is possible to obtain ΔH of a reaction using Hess's law that consist in sum the different ΔH's of other reactions until obtain the reaction you need.

Using:

<em>(1) </em>C₆H₄(OH)₂(l) → C₆H₄O₂(l) + H₂(g) ΔH: +177.4 kJ

<em>(2) </em>H₂(g) + O₂(g) → H₂O₂ (l) ΔH: -187.8 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH: -285.8 kJ

It is possible to obtain:

C₆H₄(OH)₂(l) + H₂O₂(l) → C₆H₄O₂(l) + 2H₂O(l)

From (1)-(2)+2×(3). That is:

<em>(1) </em>C₆H₄(OH)₂(l) → C₆H₄O₂(l) + H₂(g) ΔH: +177.4 kJ

<em>-(2) </em>H₂O₂(l) → H₂(g) + O₂(g) ΔH: +187.8 kJ

<em>2x(3) </em>2H₂(g) + O₂(g) → 2H₂O(l) ΔH: 2×-285.8 kJ

The ΔH you obtain is:

+177,4kJ + 187,8kJ - 2×285.8 kJ =<em> -206,4kJ</em>

b. When ΔH of a reaction is <0, the reaction is exothermic, that means that the reaction produce heat and the <em>surroundings will gain this heat.</em>

c. 20,0g of H₂O are:

20,0g×\frac{1mol}{18,01g} = <em>1,11 mol H₂O</em>

As 2 moles of H₂O are produced when -206,4kJ are given off, when 1,11mol of H₂O are produced, there are given off:

1,11mol H₂O×\frac{-206,4kJ}{2mol} =<em> -115kJ</em>

I hope it helps!

8 0
3 years ago
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