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lawyer [7]
2 years ago
15

Which shows an isomer of the molecule below?

Chemistry
2 answers:
lakkis [162]2 years ago
5 0

Answer:

B should be ur answer!

Explanation:

Sorry if im wrong :( but have a good day or night

kobusy [5.1K]2 years ago
3 0

Answer:

B

Explanation:

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At the beginning of the industrial revolution in 1850, the CO2concentration was 280 ppm. Today, it is 410 ppm.
Orlov [11]

Answer:

1. 2.04 W/m²

2. 1.63°C

Explanation:

The radiative force that the Earth receives comes from the Sun. When the Sun rays come to the surface, some of them are absorbed and then it is reflected in the space. The greenhouse gases (like CO2) blocks some of these rays, and then the surface stays warm. The excessive amount of these gases makes the surface warmer, which unbalance the climate on Earth.

1. The variation of the radiative forcing can be calculated based on the concentration of the CO2 by the equation:

ΔF = 5.35*ln(C/C0)

Where C is the final concentration, and C0 is the initial concentration.

ΔF = 5.35*ln(410/280)

ΔF = 2.04 W/m²

2. The temperature change in the Earth's surface caused by the variation of the radiative forcing can be calculated by:

ΔT = 0.8*ΔF

ΔT = 0.8*2.04

ΔT = 1.63 K = 1.63°C

6 0
3 years ago
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

4 0
3 years ago
What is the electron arrangement of bromine
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[Ar] 3d10 4s2 4p5 is the electron configuration of bromine
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Are particles in gas close together ​
Vesna [10]

Answer:

Solid particles are close together not gas particles

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Using distance and can help you identify the position of something
miskamm [114]

Answer: Length and width

Explanation:

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