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lawyer [7]
2 years ago
15

Which shows an isomer of the molecule below?

Chemistry
2 answers:
lakkis [162]2 years ago
5 0

Answer:

B should be ur answer!

Explanation:

Sorry if im wrong :( but have a good day or night

kobusy [5.1K]2 years ago
3 0

Answer:

B

Explanation:

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The energy associated with motion is
timama [110]
Yes the answer is a , kinetic energy
7 0
3 years ago
Calculate the number of moles of BaF2 in a 10.0 g sample of BaF2.
UkoKoshka [18]

Answer:

The number of moles = 0.06 moles

Explanation:

i) Formula

Number of moles = Mass of the sample ÷ Molar masses of the substances

ii) Number of moles = 10.0 ÷ (137)+(19×2)

= 10.0 ÷ 175

= 0.06 moles

5 0
3 years ago
Read 2 more answers
A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant
lakkis [162]
We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
\frac{V1}{T1} = \frac{V2}{T2}
In our case:
\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \  T2= \frac{2.50*36.00}{2.00} = 45
6 0
3 years ago
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Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
What is the molar mass of a substance?
Sveta_85 [38]

Answer:

The mass in grams of one mole of a substance.

3 0
2 years ago
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