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Arisa [49]
3 years ago
6

Wine goes bad soon after opening because the ethanol CH3CH2OH in it reacts with oxygen gas O2 from the air to form water H2O and

acetic acid CH3COOH, the main ingredient of vinegar. What mass of ethanol is consumed by the reaction of 1.9g of oxygen gas?
Chemistry
1 answer:
lyudmila [28]3 years ago
3 0

Answer: 2.73g of CH3CH2OH Will be consumed

Explanation:

CH3CH2OH + O2 —> CH3COOH + H2O

MM of CH3CH2OH = 12 + 3 +12 + 2 16 +1 = 46g/mol

MM of O2 = 16 x2 = 32

Mass conc. Of O2 = 1.9g

From the equation,

32g of O2 consumed 46g of CH3CH2OH .

Therefore, 1.9g of O2 will consume Xg of CH3CH2OH i.e

Xg of CH3CH2OH = (1.9 x 46)/32 = 2.73g

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denpristay [2]
It would be endothermic because the log is in the system.
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The Lucas test has _______ results based on the type of alcohol present because the reaction involves a _________, which is ____
Olin [163]

Answer:

1) positive

2) carbocation

3) most stable

4) faster

Explanation:

A common test for the presence of alcohols can be achieved using the Lucas reagent. Lucas reagent is a mixture of concentrated hydrochloric acid and zinc chloride.

The reaction of Lucas reagent reacts with alcohols leading to the formation of an alkyl chloride. Since the reaction proceeds via a carbocation mechanism, tertiary alcohols give an immediate reaction. Once a tertiary alcohol is mixed with Lucas reagent, the solution turns cloudy almost immediately indicating an instant positive reaction.

Secondary alcohols may turn cloudy within five minutes of mixing the solutions. Primary alcohols do not significantly react with Lucas reagent obviously because they do not form stable carbocations.

Therefore we can use the Lucas reagent to distinguish between primary, secondary and tertiary alcohols.

5 0
3 years ago
Is a light bulb chemical or physical change. State evidence why
irakobra [83]

Answer:

It is a chemical change.

Explanation:

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8 0
3 years ago
The solubility of N2 in blood can be a serious problem (the "bends") for divers breathing compressed air (78% N2 by volume) at d
OLga [1]

Answer:

The volume is 19.7 mL

Explanation:

<u>Step 1</u>: Given data

Pressure at sea level = 1.00 atm

Pressure at 50 ft = 2.47535 atm

kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm

Molarity (M) = kH x P

<u>Step 2</u>: Calculate molarity

M at sea level:

M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L

M at 50ft:

M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L

We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.

13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L

Step 3: Calculate volume

P*V=nRT

with P = 1.00 atm

with V = TO BE DETERMINED

with n =  8.04*10^-4 mol/L  *1L = 8.04*10^-4

with R= 0.0821 atm * L/ mol *K

with T = 25 °C = 273+25 = 298 Kelvin

To find the volume, we re-organize the formula to: V=nRT/P

V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml

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5 0
3 years ago
Precision Problems:
Lorico [155]

Answer:

Precision = 2.70 \± 0.1\ cm

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

Mean = \frac{18.9}{7}\ cm

Mean = 2.70\ cm

Step 2: Get The Range

Range = Highest - Lowest

Range = 2.80cm - 2.60cm

Range = 0.2\ cm

Step 3: Divide Range by 2

Approximate\ Range = \frac{1}{2}Range

Approximate\ Range = \frac{1}{2} * 0.2\ cm

Approximate\ Range = 0.1\ cm

Step 4: Determine the Precision

Precision = Average \± Approximate\ Range

Substitute 2.70 for Average and 0.1 for Approximate Range

Precision = 2.70 \± 0.1\ cm

4 0
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