Using the
V1/T1=V2/T2
where
T1=50C= 323.15K
T2= -5C=268.15 K
V2= 212m^3
substitute the given values, we will get the initial volume
V1=V2T1/T2
V1= 255.48m^3
The initial volume is 255.48m^3
Scientists ask questions, which is the basis for their investigations.
Answer:

Explanation:
From the question we are told that:
Mass of zinc 
Initial conc of HCl 
Initial volume of HCl
Molar mass of zinc
Generally the equation for reaction is mathematically given by

Generally the equation for moles of zinc
is mathematically given by



Generally the equation for moles of
is mathematically given by
Generally the reacted moles of HCl
is mathematically given by
Since
Zn:HCl =1:2
Therefore
![HCl_[reacted]=0.038*\frac{2}{1}](https://tex.z-dn.net/?f=HCl_%5Breacted%5D%3D0.038%2A%5Cfrac%7B2%7D%7B1%7D)
![HCl_[reacted]=0.076mol \ HCl](https://tex.z-dn.net/?f=HCl_%5Breacted%5D%3D0.076mol%20%5C%20HCl)
Generally the moles of HCl after Zn oxidization X is mathematically given by


Generally the conc of hydrochloride acid X is mathematically given by


Therefore Conc of HCl
