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Arisa [49]
2 years ago
6

Wine goes bad soon after opening because the ethanol CH3CH2OH in it reacts with oxygen gas O2 from the air to form water H2O and

acetic acid CH3COOH, the main ingredient of vinegar. What mass of ethanol is consumed by the reaction of 1.9g of oxygen gas?
Chemistry
1 answer:
lyudmila [28]2 years ago
3 0

Answer: 2.73g of CH3CH2OH Will be consumed

Explanation:

CH3CH2OH + O2 —> CH3COOH + H2O

MM of CH3CH2OH = 12 + 3 +12 + 2 16 +1 = 46g/mol

MM of O2 = 16 x2 = 32

Mass conc. Of O2 = 1.9g

From the equation,

32g of O2 consumed 46g of CH3CH2OH .

Therefore, 1.9g of O2 will consume Xg of CH3CH2OH i.e

Xg of CH3CH2OH = (1.9 x 46)/32 = 2.73g

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Answer: 2800 g

Explanation:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5 kg = 5000 g

\text{Number of moles}=\frac{5000g}{100g/mol}=50moles

1 mole of CaCO_3 produces = 1 mole of CaO

50 moles of CaCO_3 produces =\frac{1}{1}\times 50=50moles of CaO

Mass of CaO=moles\times {\text{Molar mass}}=50moles\times 56g/mole=2800g

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