Answer:
Explanation:
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In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
So we cancel out the moles of NaCl to obtain:
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Answer:
SO the awnser is 76.9 trust me
Explanation:
Answer:
4.186 L
Explanation:
Using the pv=nrt equation and converting the grams of O2 into mols. After finding the number of mols by dividing 5.98 by 32 (2*the atomic weight of O) you plug that into the equation. So then you have 1*V=.186875*.08206*273 then you rearrange the equation to solve for v and get 4.186 L
Missing question:
<span>(1) C2H5OH (3) C12H22O11
(2) C6H12O6 (4) CH3COOH.
Answer is: 4) CH</span>₃COOH, acetic acid.
In water, acetic acid dissociates on ions, so it can conduct electricity:
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
When we put
electrodes (cathode and anode) in acetic acid solution, positive and negative
ions migrate to electrodes.<span>
Negative acetate ions go to positive electrode
and gives electrons to electrode.
<span>Positive hydrogen ions go to negative electrode
and gain electrons.</span></span>
