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zlopas [31]
3 years ago
14

How do you write a balanced equation for the combustion ofbenzene?

Chemistry
1 answer:
forsale [732]3 years ago
4 0

Answer: The balanced chemical equation for the combustion of benzene is:

2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O

Explanation:

Combustion reactions : It is defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water as a product.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

The balanced chemical equation for the combustion of benzene will be:

2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O

By Stoichiometry of the reaction we can say that,

2 mole of benzene reacts with 15 moles of oxygen gas to produce 12 moles of carbon dioxide and 6 moles of water molecule.

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if you react 28 grams of butene with excess hydrogen how many grams of butane would you expect to get
liberstina [14]

Answer:

The correct answer is 29 grams.

Explanation:

Based on the given question, the reaction will be,

CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3

The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.

Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.

Therefore, 28 grams of butene when reacts with hydrogen gas to give,

= 58/56 * 28 = 29 grams of butane.

Hence, the mass of butane produced will be 29 grams.

8 0
2 years ago
NEED HELP QUICKLY!!! How many moles are in each of the following?
oksano4ka [1.4K]

Answer: a. 0.26mol

b. 0.000479mol

c. 1.12mol

Explanation: Please see attachment for explanation

6 0
3 years ago
What makes physical change a physical change and a chemical change a chemical change
Snowcat [4.5K]
A physical change is any change in a substances form that does not change its chemical makeup. Examples of physical changes are breaking a stick or melting ice. A chemical change occurs when atoms of a substance are rearranged, and the bonds between the atoms are broken or formed. HOPE THIS HELPS!!
6 0
2 years ago
Read 2 more answers
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
How do the isotopes hydrogen-1 and hydrogen-2 differ?
g100num [7]
<span>Hydrogen-2 has one neutron; hydrogen-1 has none</span>
4 0
3 years ago
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