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zlopas [31]
3 years ago
14

How do you write a balanced equation for the combustion ofbenzene?

Chemistry
1 answer:
forsale [732]3 years ago
4 0

Answer: The balanced chemical equation for the combustion of benzene is:

2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O

Explanation:

Combustion reactions : It is defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water as a product.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

The balanced chemical equation for the combustion of benzene will be:

2C_6H_6+15O_2\rightarrow 12CO_2+6H_2O

By Stoichiometry of the reaction we can say that,

2 mole of benzene reacts with 15 moles of oxygen gas to produce 12 moles of carbon dioxide and 6 moles of water molecule.

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What is the mass of oxygen that can be produced from 2.79 moles of lead(ll) nitrate
denis23 [38]

1.38 moles of oxygen

Explanation:

Thermal decomposition of Lead (II) nitrate is shown by the balanced equation below;

2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂

The mole ration of Lead (II) nitrate to oxygen is 2: 1

Therefore 2.76 moles of  Lead (II) nitrate will lead to production of? moles of oxygen;

2: 1

2.76: x

Cross-multiply;

2x = 2.76 * 1

x = 2.76 / 2

x = 1.38

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3 years ago
A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final
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Answer:

1.9 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 1.5 atm
  • Initial volume (V₁): 3.0 L
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  • Final pressure (P₂): 2.5 atm
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Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

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