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Alex73 [517]
3 years ago
6

The equilibrium constant for the gas phase reaction 2so2 (g) + o2 (g) 2so3 (g) is keq = 2.80 ⋅ 102 at 999 k. at equilibrium, ___

_____. the equilibrium constant for the gas phase reaction 2so2 (g) + o2 (g) 2so3 (g) is keq = 2.80 102 at 999 k. at equilibrium, ________. products predominate reactants predominate roughly equal amounts of products and reactants are present only products are present only reactants are present
Chemistry
1 answer:
masya89 [10]3 years ago
5 0
<h3><u>Answe</u>r;</h3>

b. products predominate

<h3><u>Explanation;</u></h3>

Keq = [products]/[reactants]  

if Keq > 1, the numerator is greater than the denominator.

In this case; keq = 2.80× 10^2

Which means the concentration of products is greater than that of the reactants .

Therefore, we would say that the products predorminate.

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The Handbook of Chemistry and Physics gives solubilities of the following compounds in grams per 100 mL water. Because these com
Elanso [62]

Answer:

(a) Ksp=4.50x10^{-7}

(b) Ksp=1.55x10^{-6}

(c) Ksp=2.27x10^{-12}

(d) Ksp=1.05x10^{-22}

Explanation:

Hello,

In this case, given the solubility of each salt, we can compute their molar solubilities by using the molar masses. Afterwards, by using the mole ratio between ions, we can compute the concentration of each dissolved and therefore the solubility product:

(a) BaSeO_4(s)\rightleftharpoons Ba^{2+}(aq)+SeO_4^{2-}(aq)

Molar\ solubility=\frac{0.0188g}{100mL} *\frac{1mol}{280.3g}*\frac{1000mL}{1L}=6.7x10^{-4}\frac{mol}{L}

In such a way, as barium and selenate ions are in 1:1 molar ratio, they have the same concentration, for which the solubility product turns out:

Ksp=[Ba^{2+}][SeO_4^{2-}]=(6.7x10^{-4}\frac{mol}{L}   )^2\\\\Ksp=4.50x10^{-7}

(B) Ba(BrO_3)_2(s)\rightleftharpoons Ba^{2+}(aq)+2BrO_3^{-}(aq)

Molar\ solubility=\frac{0.30g}{100mL} *\frac{1mol}{411.15g}*\frac{1000mL}{1L}=7.30x10^{-3}\frac{mol}{L}

In such a way, as barium and bromate ions are in 1:2 molar ratio, bromate ions have twice the concentration of barium ions, for which the solubility product turns out:

Ksp=[Ba^{2+}][BrO_3^-]^2=(7.30x10^{-3}\frac{mol}{L})(3.65x10^{-3}\frac{mol}{L})^2\\\\Ksp=1.55x10^{-6}

(C) NH_4MgAsO_4(s)\rightleftharpoons NH_4^+(aq)+Mg^{2+}(aq)+AsO_4^{3-}(aq)

Molar\ solubility=\frac{0.038g}{100mL} *\frac{1mol}{289.35g}*\frac{1000mL}{1L}=1.31x10^{-4}\frac{mol}{L}

In such a way, as ammonium, magnesium and arsenate ions are in 1:1:1 molar ratio, they have the same concentrations, for which the solubility product turns out:

Ksp=[NH_4^+][Mg^{2+}][AsO_4^{3-}]^2=(1.31x10^{-4}\frac{mol}{L})^3\\\\Ksp=2.27x10^{-12}

(D) La_2(MoOs)_3(s)\rightleftharpoons 2La^{3+}(aq)+3MoOs^{2-}(aq)

Molar\ solubility=\frac{0.00179g}{100mL} *\frac{1mol}{1136.38g}*\frac{1000mL}{1L}=1.58x10^{-5}\frac{mol}{L}

In such a way, as the involved ions are in 2:3 molar ratio, La ion is twice the molar solubility and MoOs ion is three times it, for which the solubility product turns out:

Ksp=[La^{3+}]^2[MoOs^{-2}]^3=(2*1.58x10^{-5}\frac{mol}{L})^2(3*1.58x10^{-5}\frac{mol}{L})^3\\\\Ksp=1.05x10^{-22}

Best regards.

7 0
4 years ago
The elements in group 17 of the periodic table are all called halogens. All halogens have the same
Nataly_w [17]

Answer:

number of valence electrons

Explanation:

All of the elements in group 17, also known as group 7A, have 7 valence electrons.

No two elements have the same atomic number nor atomic mass in elemental form.

Halogens may have any number of isotopes.

6 0
4 years ago
Read 2 more answers
You perform an experiment to measure the speed of a car over time. The
Aliun [14]

Answer:

Measure the slopes of these tangents to get v at the times concerned: 4.0 m.s. -l ... The acceleration component is smaller, about 0.5 m.s. -2 . 5 - 10 s. : The car is in gear, being ... You cannot average the speeds, since the time intervals for each half ... The driver has taken 15 minutes of the allotted 20 minutes to cover the first.

Explanation:

because youre need calculate

4 0
4 years ago
How do you think the vertical temperature
WARRIOR [948]

thermal conduction and convection processes we explain the temperature profile: warmer at the bottom and colder at the top

Temperature is a measure of the internal energy of molecules.

When the pot is on the burner, the lower part of the pot acquires energy from the flame, this energy increases the temperature of the metal that is in contact with the liquid from the bottom, by a process of thermal conduction, while the liquid in the top is kept at the same temperature.

As time progresses, the hotter lower liquid, for which it has a lower with the metal bottom heats up by conduction. density, conscientiously rise and a transfer of heat is created by convection, which raises the temperature of the hot liquid and makes the liquid fall that is colder from the upper part than at the coming into contact

This cycle is repeated heating all the liquid. But the liquid with the liquid in the lower part always at a higher temperature than the liquid in the upper part, the process stops when the liquid in the lower part reaches the boiling point, than the passage from liquid to gas, during which the temperature remains constant.

With the thermal conduction and convection processes we explain the temperature profile: warmer at the bottom and colder at the top.

Learn more about temperature transfer here:  brainly.com/question/24200572

4 0
3 years ago
I have a question, about trends in the periodic table. Mostly focusing on ionization energy. From going from right to left it in
jasenka [17]
It increases because the electrons are held tighter together by the higher effective nuclear charge. The electrons are held in lower energy orbitals and closer to the nucleus and more tightly bound and harder to remove from the atom.
5 0
3 years ago
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