Answer:
Explanation:
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In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:
Whereas n accounts for the moles which are computed below:
Thus, the entropy turns out:
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A-leads to the abrasion of rocks and minerals
A-dense vegetation cover
True
Explanation:
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Agent of weathering are wind, water and glacier.
Chemical weathering contributes to physical weathering in that it leads to the abrasion of rocks and minerals.
During chemical weathering, a rock chemically combines with materials in the environment and weakens it.
When physical weathering processes are induced, grains produced independently weakening of bonds in rocks grind against one another and wears each other off.
An area with a dense vegetation cover undergoes rapid chemical weathering:
- Plant roots penetrates deep into the rock and increases the surface area of chemical action.
- Plants produce chemicals that combines with rocks and causes them to decay.
- Since the area is always moist, chemical action becomes more severe.
Buildings and statues made of stone are subjected to the same degree of weathering as rocks exposed naturally.
This is true.
Statues and buildings weather just like rocks we find in nature.
It is the same sunshine and rain that impacts rocks that also impacts buildings and statues.
So they degrade at the same rate except they are protected.
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The answer is B. Temperate.
2 C₇H₆O₂ + 15 O₂ → 14 CO₂ + 6 H₂O
<u>Explanation:</u>
C₇H₆O₂ + O₂ → CO₂ + H₂O
First we have to balance the O- atoms, we have to put 6 in front of water so there are 12 H atoms on RHS, to balance it we need to put 2 in front of C₇H₆O₂, and so we have 14 C - atoms on LHS, 28 + 6 = 34 O - atoms on RHS, so we have to put 15 in front of Oxygen in LHS, so that each and every atom in the equation gets balanced now. The balanced equation is, 2 C₇H₆O₂ + 15 O₂ → 14 CO₂ + 6 H₂O
The volume of water that will be produced from the reaction will be 6.3 mL
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:
The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.
Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles
Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles
Thus, hydrogen sulfide is the limiting reagent.
Mole ratio of hydrogen sulfide to water = 1:2.
Equivalent mole of water = 0.175 x 2 = 0.35 moles
Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.
1 gram of water = 1 ml.
Thus, 6.3 grams of water will be equivalent to 6.3 mL
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