Question

A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.

Answer 1

Answer:

812 kPa

Explanation:

• According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.

• Mathematically, $P\alpha \frac{1}{V}$

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

$P2=\frac{P1V1}{V2}$

Replacing the known variables with the values;

$P2=\frac{(101.5)(2.0L)}{0.25L}$

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa