Answer:
<u>3.16 liters O2</u>
Explanation:
I'll assume the C3H3 is really supposed to read C3H8, for propane.
C3H3(g) + 5 O2 (g) + 3 CO2 (g)+ 4 H20 (g)
<u>C3H</u><em><u>8</u></em><u>(g) + 5 O2 (g) + 3 CO2 (g)+ 4 H20 (g)</u>
It is unlikely that all the gases involved in this reaction will remain at STP due to the large amount of energy released, we'll assume STP since:
1) We are told STP and no other information is given, and
2) STP makes the problem much easier, since all gasses occupy 22.4 liters per mole of that gas.
The balanced equation tells us we need 5 moles of O2 for every 1 mole of C3H3: a molar ratio of 5/1 (moles O2/moles C3H8).
Calculate moles C3H8 in 0.632 liters of the stuff [metric term for compound]:
(0.632 liters)/(22.4 liters/mole) = 0.0282 moles C3H8
This means we'll need 5 times that number for the amount of O2 required. That comes to 0.1411 moles O2.
Convert that to volume: (0.1411 moles O2)*(22.4 liter/mole) = 3.16 liters O2
Plant cells have chloroplasts and a cell wall..... chloroplasts are the organelle that conduct photosynthesis..... and the cell wall is like an extra barrier for the cell membrane.... I hope this helps, have an amazing day/or night.... and god bless uuuu!!!
<3
Answer:
there it is fella tried on ma own consciousness
The angle of incoming sunlight varies at different places.
Balance the equation first:
2 Fe+6 HNO3→2 Fe(NO3)3+3H2
Then calculate mass of Iron :
4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe
Now use Stoichiometry:
371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3
Convert moles of nitric acid to grams
19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3
